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3 years ago

Two thermometers are calibrated, one in de

Physics

1 answer:

zlopas [31]3 years ago

6 0

-40 c = -40 f but k would be 233.15

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Water is flowing from a garden hose. A child places his thumb to cover most of those outlet, causing a thin jet of high speed wa

Oxana [17]

Answer: maximum height= 40.8m

Explanation: shown in the attachment.

Goodluck

3 0

2 years ago

Relativistic velocity is of the order of _____ of velocity of light A- 1/15th of the velocity of light B-1/20th of the velocity

ratelena [41]

Answer:

Relativistic velocity is of the order of 1/10th of the velocity of light

Explanation:

We define relativistic speed (or velocity) as a speed that is a significant fraction of the speed of light: c = 3*10^8 m/s

Such that for these speeds, the special relativity theory starts to apply (the relativity effects starts to apply).

Usually, we define relativistic speeds as those that are of the order (or larger) of c/10, which is one-tenth of the speed of light.

Then the correct option is C:

Relativistic velocity is of the order of 1/10th of the velocity of light

4 0

3 years ago

A 3 Ω resistor, an 8 Ω resistor, and a 14 Ω resistor are connected in parallel across a 6 V battery. Determine the equivalent re

Schach [20]

Answer:

R=25Ω

Explanation:

Given data:

R1=3 Ω

R2=8 Ω

R3=14 Ω

V=6

Now,

To Find,

R=?

Formula

R=R1+R2+R3

put the values,

R=3+8+14

R=25Ω

6 0

3 years ago

D.) How can you demonstrate the magnetic force? Write with an example

Lena [83]

Explanation:

d) Magnetic force is the power that pulls materials together (magnet e. g iron)

an example :how magnet can pick up a coin.

e) frictional force produces when two surfaces are in contact with each other.

effects of friction : I) it produces heat

II) it causes loss in power.

4 0

2 years ago

The wavelength of the visible line in the hydrogen spectrum that corresponds to m = 5 in the Balmer equation is: A. 656 nm. B. 4

BaLLatris [955]

Answer:

The wavelength of the visible line in the hydrogen spectrum is 434 nm.

Explanation:

It is given that, the wavelength of the visible line in the hydrogen spectrum that corresponds to n₂ = 5 in the Balmer equation.

For Balmer series, the wave number is given by :

$\dfrac{1}{\lambda}=R(\dfrac{1}{n_1^2}-\dfrac{1}{n_2^2})$

R is the Rydberg's constant

For Balmer series, n₁ = 2. So,

$\dfrac{1}{\lambda}=1.097\times 10^7\times (\dfrac{1}{2^2}-\dfrac{1}{5^2})$

$\lambda=4.34\times 10^{-7}\ m$

$\lambda=434\ nm$

So, the wavelength of the visible line in the hydrogen spectrum is 434 nm. Hence, this is the required solution.

6 0

2 years ago