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Lady bird [3.3K]

2 years ago

9

What is the product of (2x+3)(4x²-5x+6)

1 answer:

Rasek [7]2 years ago

3 0

Answer:

24x^3-30x^2+36x

Step-by-step explanation:

you distribute.

(2x+3)(4x^2-5x+6)

distribute the 2x first

3(4x^2*2x-5x*2x+6*2x)

then simplify

3(8x^3-10x^2+12x)

then distribute again (I'm distributing and multiplying it out in this step)

24x^3-30x^2+36x

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If M is the set of all square numbers less than 80 and N is the set of all non-negative even numbers that are under 30, Write th

Nat2105 [25]

Answer:

Step-by-step explanation:

All square numbers are numbers formed by squaring a single number. If M is the set of all square numbers less than 80, then

M = (4, 9, 16, 25, 49, 64)

Even numbers are numbers that are divisible by 2 without remainder.

If N is the set of all non-negative even numbers that are under 30, then

N = (2, 4, 6, 8 ,10, 12, 14, 16,18,20, 22, 24, 26,28)

It will not include 30 because we want even numbers under 30

8 0

3 years ago

1/6 + 3/8 <br> A. 4/6<br> B. 4/8 <br> C. 4/14<br> D. 13/24

Naddika [18.5K]

Here is you're answer:

In order to get you're answer you need to find the common denominator then add.

$\frac{1}{6} + \frac{3}{8}$
Find the common denominator:
$CD = 48$
$= \frac{26}{48}$
Simplify:
$\frac{26}{48} \div 2 = \frac{13}{24}$
$= \frac{13}{24}$

Therefore you're answer is option D "13/24."

Hope this helps!

8 0

2 years ago

Find the angle between the given vectors. Round your answer, in degrees, to two decimal places. u=⟨2,−6⟩u=⟨2,−6⟩, v=⟨4,−7⟩

NISA [10]

Answer:

$\theta = 108.29$

Step-by-step explanation:

Given

$u =$

$v =$

Required:

Calculate the angle between u and v

The angle $\theta$ is calculated as thus:

$cos\theta = \frac{u.v}{|u|.|v|}$

For a vector

$A =$

$A = a * b$

$cos\theta = \frac{u.v}{|u|.|v|}$ becomes

$cos\theta = \frac{.}{|u|.|v|}$

$cos\theta = \frac{2*6+4*-7}{|u|.|v|}$

$cos\theta = \frac{12-28}{|u|.|v|}$

$cos\theta = \frac{-16}{|u|.|v|}$

For a vector

$A =$

$|A| = \sqrt{a^2 + b^2}$

So;

$|u| = \sqrt{2^2 + 6^2}$

$|u| = \sqrt{4 + 36}$

$|u| = \sqrt{40}$

$|v| = \sqrt{4^2+(-7)^2}$

$|v| = \sqrt{16+49}$

$|v| = \sqrt{65}$

So:

$cos\theta = \frac{-16}{|u|.|v|}$

$cos\theta = \frac{-16}{\sqrt{40}*\sqrt{65}}$

$cos\theta = \frac{-16}{\sqrt{2600}}$

$cos\theta = \frac{-16}{\sqrt{100*26}}$

$cos\theta = \frac{-16}{10\sqrt{26}}$

$cos\theta = \frac{-8}{5\sqrt{26}}$

Take arccos of both sides

$\theta = cos^{-1}(\frac{-8}{5\sqrt{26}})$

$\theta = cos^{-1}(\frac{-8}{5 * 5.0990})$

$\theta = cos^{-1}(\frac{-8}{25.495})$

$\theta = cos^{-1}(-0.31378701706)$

$\theta = 108.288386087$

<em></em> $\theta = 108.29$ <em> (approximated)</em>

4 0

2 years ago

Write a number with the digit 8 in the tens place

koban [17]

80 is a good one to start with.

After that, you can move on to 83, 481, 1687, and 102,974,589 .

6 0

3 years ago

Read 2 more answers

What is the slope of the line? <br>y = -2/7x<br><br>A. -2<br>B. -2/7<br>C. 0<br>D. 2/7

denis-greek [22]

The slope of the line is -2/7

3 0

2 years ago

Read 2 more answers