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Hoochie [10]
3 years ago
10

Any help? I need to describe the change of the equation, in terms of it getting thinner (>) or wider (<). I don't exactly

understand how to do this, can anyone explain? ​

Mathematics
1 answer:
vovangra [49]3 years ago
4 0

9514 1404 393

Answer:

  no change to the width of the curve

Step-by-step explanation:

Your terminology and use of symbols (>, <) are unusual, so we're not sure what your question is.

The equation represents a transformation of the parent function

  y = x²

The transformation (replacing x with (x-4)) is a translation right 4 units. This can be seen in the attached graph. The "parent function" is shown in red. Your function is shown in blue.

Nothing about this transformation changes the width of the curve, so it is neither thinner nor wider than it was originally. The description usually used if the curve is narrower or wider is "horizontal compression" or "horizontal expansion."

The curve does get wider for larger y-values. It is said to "open upward".

__

<em>Additional comment</em>

The symbols < and > stand for "is less than" and "is greater than", respectively. They are occasionally used as "angle brackets" to identify vectors or tokens of one sort or another. Sometimes, they are used to signify an angle when the appropriate ∠ symbol is not available. This is the first time in many years of studying math that I have seen them in the context of "thinner" and "wider."

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6 0
3 years ago
A, B &amp; C form the vertices of a triangle.
Savatey [412]

Answer:

BC = 17.2.

Step-by-step explanation:

Since CAB = 90º, this is a right triangle.

The triangle format is given below:

C

A           B

We have that AB = 8.6, and angle B measures 60º.

Length of BC:

BC is the hypotenyse.

Side AB is adjacent to angle B = 60º.

In a right triangle, angle \alpha, it's adjacent side with length s and the hypotenuse h are related by the cosine of the angle, that is:

\cos{\alpha} = \frac{s}{h}

In this question, we have an angle of 60º, with has cosine 0.5. We also have that side AB = s = 8.6, and the hypotenuse h is side BC. So

\cos{\alpha} = \frac{s}{h}

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4 0
3 years ago
Write 16.3 as a mixed number
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Answer:

Step-by-step explanation:

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4 0
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Read 2 more answers
Find an equation of the line in the form ax+by=c whose​ x-intercept is 12 and​ y-intercept is 4​, where​ a, b, and c are integer
Lostsunrise [7]

Answer:

The equation of the line  in ax+by=c  form where a,b,c  are integers with no factor common to all​ three, and greater than or equal 0 is:

x+3y=12

Step-by-step explanation:

Given:

x-intercept = 12

y-intercept = 4

To find the equation of line in the form ax+by=c where a,b,c  are integers with no factor common to all​ three, and greater than or equal 0.

Solution:

The x-intercept is the point at which the line cuts the x-axis. The point of x-intercept is given as (x,0)

Thus, on point of the line is (12,0)

The y-intercept is the point at which the line cuts the y-axis. The point of y-intercept is given as (0,y).

Thus, on point of the line is (0,4)

Using the two points we can find the slope of the line using the slope formula.

m=\frac{y_2-y_1}{x_2-x_1}

So, slope of the line can b given as:

m=\frac{4-0}{0-12}

m=\frac{4}{-12}

m=-\frac{1}{3}

The slope intercept form of the equation of he line is given as:

y=mx+b

where m represents slope of the line and b represents the y-intercept.

So, the equation of the line can be given as:

y=-\frac{1}{3}x+4

Multiplying each term by 3 to remove fraction.

3y=3.-\frac{1}{3}x+4(3)

3y=-x+12

Adding x both sides.

3y+x=-x+x+12

3y+x=12

Thus, the equation of the line  in ax+by=c  form where a,b,c  are integers with no factor common to all​ three, and greater than or equal 0 is:

x+3y=12

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