River shore is located at distance
speed of the woman is given as
now the time taken by the woman to cover the distance is
for the same time interval the dog will run to and fro with speed 4.5 m/s
so the total distance moved by the dog is given by
<em>so the total distance that dog will move is 7200 m or 7.2 km</em>
If you look closely at the question it's pretty easy but since I know what your here for the answer is indeed relative
Answer:
165.8 V/m
Explanation:
The capacitance of a long concentric cylindrical shell of length, L and inner radius, a and outer radius, b is C = 2πε₀L/㏑(b/a)
Since the charge on the cylindrical shells, Q = CV where V = the potential difference across the capacitor(which is the potential difference between the concentric cylindrical shells)
V = Q/C
V = Q ÷ 2πε₀L/㏑(b/a)
V = Q㏑(b/a)/2πε₀L
So, the potential difference per unit length V' is
V' = V/L = Q㏑(b/a)/2πε₀
Given that a = inner radius = 1.5 cm, b = outer radius = 5.6 cm and Q = 7.0 nC = 7.0 × 10⁻⁹ C and ε₀ = 8.854 × 10⁻¹² F/m substituting the values of the variables into the equation, we have
V' = Q㏑(b/a)/2πε₀
V' = 7.0 × 10⁻⁹ C㏑(5.6 cm/1.5 cm)/(2π × 8.854 × 10⁻¹² F/m)
V' = 7.0 × 10⁻⁹ C㏑(3.733)/(55.631 × 10⁻¹² F/m)
V' = 7.0 × 10⁻⁹ C × 1.3173/(55.631 × 10⁻¹² F/m)
V' = 9.2211 × 10⁻⁹ C/(55.631 × 10⁻¹² F/m)
V' = 0.16575 × 10³ V/m
V' = 165.75 V/m
V' ≅ 165.8 V/m
Answer:
The student is going at the bottom of the slide with a velocity of 8.66 m/s
Explanation:
Given;
mass of the student, m = 74 kg
height of the water slide, h = 11.3 m
work done, W = -5.42 × 10³ J
Apply work energy theorem;
Therefore, the student is going at the bottom of the slide with a velocity of 8.66 m/s