Answer:
Polarized sunglasses
Explanation:
Polarized sunglasses are comprised of polarized lenses which have a special type of filter that can block the strong reflected light emitted from the sun. It also helps in decreasing the beam of light and eventually reduces the discomfort during the bright sunlight. It reduces the eye strain to see the objects clearly and visibly.
These sunglasses are mostly used while driving and protects our eyes from the harmful incoming solar lights and enables a person to observe the path clearly without any disturbance.
Pretty sure a it’s d since every cm increases by 5N meaning 3 cm would increase it by 15N
Answer:
a ) I= 1.635-i0.0021 b) ∅= -0.074
Explanation:
a) reactive impeadance= 2πfL
=2(3.14)(147)(0.158)
=145.86 Ω
Z= 171+j145.86
I=V/Z
I=278/(171+j145.86)
I= 1.635-i0.0021
b) ∅=inv.tan (-0.0021/1.635)
∅=-0.074
Answer:

Explanation:
The definition of angular velocity is as follows:

where
is the angular velocity, and
is the frequency.
Frequency can also be represented as:

where
is the period, (the time it takes to conclude a cycle)
with this, the angular velocity is:

The period T of rotation around the sun 365 days, thus, the angular velocity:

if we want the angular velocity in rad/second, we need to convert the 365 days to seconds:
Firt conveting to hous

then to minutes

and finally to seconds

thus, angular velocity in rad/second is:

You can just use basic
trigonometry to solve for the x & y components.
<span>vector a = 10cos(30) i +
10sin(30) j = <5sqrt(3), 5></span>
vector b is only slightly harder because the angle is relative
to vector a, and not the positive x-axis. Anyway, this just makes vector b with
an angle of 135deg to the positive x-axis.
<span>vector b = 10cos(135) i +
10sin(135) j = <-5sqrt(2), 5sqrt(2)></span>
So
now we can do the questions:
r = a + b
r = <5sqrt(3)-5sqrt(2), 5+5sqrt(2)>
(a)
5sqrt(3)-5sqrt(2)
(b)
5+5sqrt(2)
(c)
|r|
= sqrt( (5sqrt(3)-5sqrt(2))2 + (5+5sqrt(2))2 )
=
12.175
(d)
θ = tan-1 (
(5+5sqrt(2)) / (5sqrt(3)-5sqrt(2)) )
θ
= 82.5deg
<span> </span>