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TEA [102]
3 years ago
5

Two physics students, Ben and Bonnie, are in the weightlifting room. Bonnie lifts the 50 kg barbell over her head (approximately

.60 m) 10 times in one minute; Ben lifts the 50 kg barbell the same distance over his head 10 times in 10 seconds. Which student does the most work? Which student delivers the most power? Explain your answers.
Physics
1 answer:
KatRina [158]3 years ago
5 0

Answer:

Both of them

Explanation:

You might be interested in
which of the following statements is correct when describing the forces at work on a bridge a. wires are in tension B. large pos
stiv31 [10]

Answer:

All the statements are true

Explanation:

A) Wires are in tension.

It is true because the loads exerted on the bridge are taken by each of the cables of the bridge. these cables transmit the force to the pillars or columns of the bridge. (check the image 01)

B) Large posts are in compression.

It is true each of the loads of the cables is tension, are transmitted to the columns of the bridge, in this way the balance will be maintained (check the image 01)

C) The bridge deck is both in tension and compression.

Yes it is true, the superior part of the deck will be in compression and the inferior part will be in tension, this can be seen in the image 02

8 0
4 years ago
Why is it important to use the correct number of significant digits when
Pani-rosa [81]

A. To show how precise your measurements were

Explanation:

It is important to use the correct number of significant digits when reporting the results of an experiment because they show how precise measurement are.

  • Precision is the ability to reproduce a particular set of results in an experiment.
  • Every instrument have their precision level.
  • The precision levels shows to what extent the values obtained can be trusted..
  • Significant figures are not only important in recording measurements, they are also needed for calculations in science.

Learn more:

Significant figures brainly.com/question/4967602

#learnwithBrainly

5 0
4 years ago
Find the height or length of these natural wonders in km, m, and cm.A. A cave system with a mapped length of 354 miles.B. A wate
cricket20 [7]

Explanation:

Some standard unit conversion are 1 mile = 1.609344 km, 1 ft.= 30.48 cm,

1 km= 1000 m or 1 m = 0.001 km and 1 m= 100 cm or 1 cm=0.01 m.

Now, use these values to convert the given lengths.

A. length of cave = 5 miles (given)

From standard value 1 mile = 1.609344 km

\Rightarrow 5 miles = \times 1.609344 km= 8.04672 km,

\Rightarrow 5 miles =8.04672 \times 1000 m= 8046.72 m [ as 1 km = 1000 m]

\Rightarrow 5 miles = 8046.72 \times 100 cm=804672 cm

B. Height of the waterfall = 1235 ft. (given)

1 ft.= 30.48 cm [ from standard value]

\Rightarrow 1235.2 ft.= 1235.2\times 30.48 cm=37648.896 cm,

\Rightarrow 1235.2 ft.=37648.896 \times 0.01 m =376.48896 m [ as 1 cm = 0.01 m]

\Rightarrow 1235.2 ft.=376.48896 \times 0.001 km =0.37648896 km [ as 1 m = 0.001 km]

C. Height of the mountain= 21320 ft. (given)

From standard value: 1 ft.= 30.48 cm

\Rightarrow 21320 ft.= 21320 \times 30.48 cm=649833.6 cm,

\Rightarrow 21320 ft.=649833.6 \times 0.01 m =6498.336 m [ as 1 cm = 0.01 m]

\Rightarrow 21320 ft.=6498.336 \times 0.001 km =6.498336 km [ as 1 m = 0.001 km].

D. Depth of canyon =6630 ft.

From standard value: 1 ft.= 30.48 cm

\Rightarrow 6630 ft.= 6630 \times 30.48 cm=202082.4 cm,

\Rightarrow 6630 ft.=202082.4  \times 0.01 m =2020.824  m [ as 1 cm = 0.01 m]

\Rightarrow 6630 ft.=2020.824  \times 0.001 km =2.020824  km [ as 1 m = 0.001 km].

4 0
4 years ago
PLZ HELP ME
bonufazy [111]

Answer:

1. The stone will strike the ground 49.46 m from the base of the cliff

2. A) Approximately 0.542 seconds

B)  Approximately 3.69 m/s

3. A) The time the ball spends in the air is approximately 4.0775 s

B) The horizontal range is approximately  141.25 m.

Explanation:

1. The time it takes the stone to land is given by the equation, t = √(h/(1/2 × g)

∴ t = √(30/(1/2 × 9.81)) ≈ 2.473 seconds

The horizontal distance covered by the stone in that time = 20 × 2.473 ≈ 49.46 m

The stone will strike the ground 49.46 m from the base of the cliff

2. A) The time the ball spends in the air = t = √(h/(1/2 × g)

∴ t = √(1.44/(1/2 × 9.81)) ≈ 0.542 seconds

B) The initial horizontal velocity, u = Horizontal distance/(Time) = 2/0.542 ≈ 3.69 m/s

The initial horizontal velocity ≈ 3.69 m/s

3. A) The time the ball spends in the air is given by the following equation;

t = 2 × u × sin(θ)/g = 2 × 40 × sin(30)/9.81 ≈ 4.0775 s

t ≈ 4.0775 s

B) The horizontal range, R, of the  ball is given by the equation for the range of a projectile as follows;

Range, R = \dfrac{u^2 \times sin (2 \cdot \theta) }{g}

Substituting the known values, gives;

Range, R = \dfrac{40^2 \times sin (2 \times 30^{\circ}) }{9.81} \approx 141.25 \ m

The horizontal range ≈ 141.25 m.

4 0
3 years ago
Which of the following statements is/are true?Check all that apply.a. A dissipative interaction permits a two-way conversion bet
oee [108]

Answer:

a. A dissipative interaction permits a two-way conversion between kinetic and potential energies.

FALSE

in dissipative type of forces energy is not conserved so it is not possible

b. A nondissipative interaction permits a two-way conversion between kinetic and potential energies.

TRUE

in non dissipative type of force there is no energy loss so we can use energy conservation

c. A potential energy function can be specified for a dissipative interaction.

FALSE

Here potential energy is not defined for dissipative type of forces

d. A potential energy function can be specified for a nondissipative interaction.

TRUE

negative gradient of potential energy is equal to non dissipative type of forces

F = -\frac{dU}{dr}

3 0
4 years ago
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