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TEA [102]
3 years ago
5

Two physics students, Ben and Bonnie, are in the weightlifting room. Bonnie lifts the 50 kg barbell over her head (approximately

.60 m) 10 times in one minute; Ben lifts the 50 kg barbell the same distance over his head 10 times in 10 seconds. Which student does the most work? Which student delivers the most power? Explain your answers.
Physics
1 answer:
KatRina [158]3 years ago
5 0

Answer:

Both of them

Explanation:

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How many atoms of each element are in the chemical formula P205?
Irina-Kira [14]

2 atoms of P (phosphorus) and 5 atoms of O (oxygen)

Explanation:

The chemical formula of a generic compound is written as

A_n B_m

where

A and B are the symbols of the elements contained in the compound

n and m are the number of atoms of each element, A and B respectively

In this problem, the compound given is

P_2 O_5

where:

- P is the symbol of the chemical element phosphorus

- O is the symbol of the chemical element oxygen

We see that the number following P is 2, so there are 2 atoms of phosphorus, while the number following O is 5, so there are 5 atoms of oxygen.

Learn more about compounds here:

brainly.com/question/10216585

brainly.com/question/2861241

brainly.com/question/10585691

#LearnwithBrainly

5 0
3 years ago
A block of mass of 10kg is being pushed on a tabletop downwards by a force of 200N. There is no acceleration in the problem. Cal
lord [1]
F = M*A 

200N*10KG is 2000 newtons

so 2000 newton's is the normal force that is being exerted on the block 
7 0
3 years ago
In which activity is no work done?
sleet_krkn [62]
The answer is B because you are not using force or energy as if you were if you were to lift or push something.
3 0
4 years ago
Read 2 more answers
a 5.0 kg ball is dropped from a 2.5 m high window. what is the velocity of the ball just before it hits the ground?
julsineya [31]

Answer:

Approximately 7.0\; \rm m \cdot s^{-1}.

Assumption: the ball dropped with no initial velocity, and that the air resistance on this ball is negligible.

Explanation:

Assume the air resistance on the ball is negligible. Because of gravity, the ball should accelerate downwards at a constant g = 9.81 \; \rm m \cdot s^{-2} near the surface of the earth.

For an object that is accelerating constantly,

v^2 - u^2 = 2\, a \, x,

where

  • u is the initial velocity of the object,
  • v is the final velocity of the object.
  • a is its acceleration, and
  • x is its displacement.

In this case, x is the same as the change in the ball's height: x = 2.5\; \rm m. By assumption, this ball was dropped with no initial velocity. As a result, u = 0. Since the ball is accelerating due to gravity, a = 9.81\; \rm m \cdot s^{-2}.

v^2 - u^2 = 2\, g \cdot h.

In this case, v would be the velocity of the ball just before it hits the ground. Solve for

v^2 = 2\, a\, x + u^2.

\begin{aligned}v &= \sqrt{2\, a\, x + u^2} \\ &= \sqrt{2\times 9.81 \times 2.5 + 0} \\ &\approx 7.0\; \rm m\cdot s^{-1}\end{aligned}.

3 0
3 years ago
}Un alumno utiliza una balanza de dos platillos y coloca un objeto en el platillo derecho. Luego coloca las masas patrón en el i
Feliz [49]

Answer:

no se

Explanation:

y la verga de da en la cara

6 0
3 years ago
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