15/4 = 3.75 m/s2. Do not try this formula all the time. This is an exception
Answer:
v = 9.07 m/s
the vertical component of the velocity of the fish relative to the water when it hits the water is 9.07 m/s
Explanation:
Given;
An eagle is flying horizontally at a speed of 4.6 m/s
Initial horizontal velocity uh = 4.6 m/s
Initial vertical velocity uy = 0
Height to fall d = 4.2 m
Acceleration due to gravity g = 9.8 m/s^2
The final vertical velocity of the fish when it hits the water can be calculated using the equation of motion;
v^2 = u^2 + 2as
v^2 = uy^2 + 2gd
uy = 0
v^2 = 2gd
v = √(2gd)
Substituting the given values;
v = √(2×9.8×4.2)
v = 9.073036977771 m/s
v = 9.07 m/s
the vertical component of the velocity of the fish relative to the water when it hits the water is 9.07 m/s
<h3><u>Answer;</u></h3>
<u>An increase in pressure favors the formation of ozone </u>
<h3><u>Explanation;</u></h3>
- Ozone, O3, decomposes to molecular oxygen in the stratosphere according to the reaction
2O3(g) ⇆ 3O2 (g).
- There are more moles of product gas than moles of reactant gas. An increase in total pressure increases the partial pressure of each gas, shifting the equilibrium towards the reactants.
- Therefore; an increase in pressure favors backward reactions towards the formation of ozone.
<span>A ball is thrown downward at 5ms from roof 10m high its velocity when it reaches the ground is 0 m/s. This is because it already dropped from the ground or x axis. So the velocity already stopped. </span>
