Answer:
Distance, S = 110 meters
Explanation:
Given the following data;
Initial velocity = 15 m/s
Acceleration = 4 m/s²
Time = 5 seconds
To find the distance covered, we would use the second equation of motion;
Where;
S is the distance covered or displacement of an object.
u is the initial velocity.
a is the acceleration.
t is the time.
Substituting the values into the equation, we have;
Distance, S = 110 meters
Explanation:
Using,
S = vi*t + 1/2*a*tr^2
vi = initial velocity = 0 m/s
S = 1/2 * 9.8 * tr^2
= 4.9tr^2.
S = vf * (ta - tr)
4.9tr^2 = 330 * (9.3 - tr)
4.9tr^2 - 3069 + 300 * tr)
Using general quadratic equation,
tr = 8.93 s.
S = 4.9 * (8.93)
= 390.75 m.
B.
Therefore,
S = 4.9 * (9.3)^2
= 423.8 m.
The height of the cliff would be overestimated.
<h2>Answer:</h2>
<u>It is deflecting towards point X because it is hitting the proton or neutron</u>
<h2>Explanation:</h2>
The experiment shows the model of Rutherford atomic model and he concluded that every atom contains a nucleus where all of its positive charge and most of its mass are concentrated. So when the ray passes straight it meant that most of the place inside atom is empty but when it directly hits the neucleus it would come back at 180 degrees and when it passes with neucleus it bends away with the angle of 90 degrees.