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Arada [10]
3 years ago
9

Cheryl spends 3/10 of her savings on a book and 2/5 of it on a pen. What fraction of her savings does Cheryl spend.

Mathematics
2 answers:
GenaCL600 [577]3 years ago
8 0
Cheryl spends 7/10 of her savings 
Musya8 [376]3 years ago
5 0
7/10 is the answer k
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868/31 long division
pentagon [3]

28.                            THATS THE CORRECT ANSWER

3 0
3 years ago
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Find the values of x and y.<br> 2(5x- 5)°<br> (5y + 5)º (7y - 9°<br> (6x + 50)
Amanda [17]

The values of x and y are 15 and 7 respectively

The angles formed from the intersection of two lines at X are equal and vertically opposite angles.

From the figure shown, we can conclude that:

2(5x-5) = 6x + 50 (vertically opposite angle)

Expand

10x - 10 = 6x + 50

10x - 6x = 50 + 10

4x = 60

x = 60/4

x =15

Similarly;

5y + 5 = 7y - 9

Collect the like terms;

5y - 7y = -9 - 5

-2y = -14

y = 14/2

y = 7

Hence the values of x and y are 15 and 7 respectively

Learn more here: brainly.com/question/15198257

4 0
2 years ago
What is the average rate of change between:
Alex_Xolod [135]
The average rate of change is 1
2-1=1
3-2=1
4-3=1
7 0
2 years ago
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Does anyone know what the answer is
Natali5045456 [20]

Answer:

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3 years ago
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Suppose that the weights of 5400 registered female Labrador retrievers in the United States are distributed normally with a mean
Maurinko [17]

Answer:

N= 4543 Labrador retrievers

Step-by-step explanation:

We know that the mean \mu is:

\mu = 62.5

and the standard deviation \sigma is:

\sigma=2.5

The probability that a randomly selected Labrador retriever weighs less than 65 pounds is:

P(X

We calculate the Z-score for X =65

Z = \frac{X-\mu}{\sigma}\\\\Z =\frac{65-62.5}{65}=1

So

P(X

Looking in the table for the standard normal distribution we have to:

P(Z.

Finally the amount N of Labrador retrievers that weigh less than 65 pounds is:

N = P(X

N = 0.8413*5400

N= 4543 Labrador retrievers

6 0
3 years ago
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