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iragen [17]
3 years ago
9

Plz help whats alex error i beg help i will give 19 points and brainlist

Mathematics
2 answers:
Alenkasestr [34]3 years ago
7 0

Answer:

Alex timed 7 by 2 instead of 7 times 7 because 7^2 is an exponent.

ElenaW [278]3 years ago
7 0
The person above is correct
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The volume is <span>1658 hope it helps <3</span>
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Write the equation in standard form for the circle that has a diameter with endpoints (6, -9)
nevsk [136]

Answer:

Step-by-step explanation:

By definition a diameter goes through the center of the circle.  So if we find the midpoint of the diameter, we will have the h and k of the center.  Then we will use one of the points ON the circle as x and y and solve for r.  Here goes:

M=(\frac{6+(-6)}{2},\frac{-9+(-9)}{2}) to get a midpoint/center of (0, -9).

The standard form of a circle is

(x-h)^2+(y-k)^2=r^2

Filling in with h, k, x, and y:

(6-0)^2+(-9-(-9))^2=r^2 which simplifies to

6^2+0^2=r^2  so

r^2=36

Now we can write the equation of the circle:

x^2+(y+9)^2=36

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3 years ago
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3. the quotient of some number and six
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2. Write a quadratic equation with roots (-2,0) and (4,0) that has a minimum value<br> of -36
Brums [2.3K]

Answer:

f(x) = 4*(x+2)*(x-4) factorized formula

f(x) = 4x^2 - 8x - 32 polynomical formula

Step-by-step explanation:

Lets assume the factorized formula of a quadratic function:

f(x) = a*(x-x1)^2 * (x-x2)^2

where "a" is a coefficient and x1, x2 are the roots of the function. Then replacing the given roots:

f(x) = a*(x+2)*(x-4)

because its told us that -36 is the minimum value of the function we can say that its concave, then this value is actually the component in the Y axis of the vertex. To find the component in the X axis of the vertex we have to make the adding between the roots and divide this value by 2, this last is because a quadratic function is a symetrical function. Lets call the component at the X axis of the vertex as Xv, then:

Xv=(x1+x2)/2

Xv=(-2+4)/2

Xv=1

Therefore now we have a point of the function and its P=(1,-36) this point is the vertex of the function too.

Now the last thing to do is to find the value of the coefficient "a". We can find it by replacing the point of the vertex obtained before.

-36 = a*(1+2)*(1-4)

-36 = a*(3)*(-3)

-36 = a*(-9)

4 = a

Finally the equation is:

f(x) = 4*(x+2)*(x-4)

if we expand this function we find the polynomical form of this function

f(x) = 4x^2 - 8x - 32

6 0
4 years ago
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