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Mrac [35]
2 years ago
12

In a triangle with vertices A,B and C, if C =64° and the lengths AC= 40mm and BC= 70mm find the length AB using cosine rule

Mathematics
1 answer:
boyakko [2]2 years ago
5 0

Answer:

63.6mm

Step-by-step explanation:

According to cosine rule;

AB² = BC²+AC²-2(BC)(AC)cos m<C

Substitute the given values

AB² = 70²+40²-2(70)(40)cos 64

AB² = 4900+1600-5600cos64

AB² = 6500-5600(0.4384)

AB² = 6500-2,454.87

AB² = 4,045.12

AB = √4,045.12

AB = 63.6mm

Hence the length of AB is 63.6mm

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4 0
2 years ago
How many moles of oxygen are required to burn 3.0 mole of C10H8 (naphthalene)?
astra-53 [7]

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6 0
3 years ago
Please help ....this is due tomorrow
marshall27 [118]

A) 0.15 times $2,570 = $412.50

B) $122.85 times 2( 12 ) = $2,948.40

C) $2,570

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5 0
3 years ago
What is 5/6 times 12
viktelen [127]
5/6 × 6 = 5 so 5/6 times 12= 10 
8 0
3 years ago
Read 2 more answers
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