In a triangle with vertices A,B and C, if C =64° and the lengths AC= 40mm and BC= 70mm find the length AB using cosine rule

Mathematics

1 answer:

boyakko [2]2 years ago

5 0

Answer:

63.6mm

Step-by-step explanation:

According to cosine rule;

AB² = BC²+AC²-2(BC)(AC)cos m<C

Substitute the given values

AB² = 70²+40²-2(70)(40)cos 64

AB² = 4900+1600-5600cos64

AB² = 6500-5600(0.4384)

AB² = 6500-2,454.87

AB² = 4,045.12

AB = √4,045.12

AB = 63.6mm

Hence the length of AB is 63.6mm

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Answer:

a) $P(X=0)=(10C0) (0.15)^0 (1-0.15)^{10-0}= 0.1969$

b) $P(X=3)=(10C3) (0.15)^3 (1-0.15)^{10-3}= 0.1298$

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Step-by-step explanation:

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