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Mrac [35]
2 years ago
12

In a triangle with vertices A,B and C, if C =64° and the lengths AC= 40mm and BC= 70mm find the length AB using cosine rule

Mathematics
1 answer:
boyakko [2]2 years ago
5 0

Answer:

63.6mm

Step-by-step explanation:

According to cosine rule;

AB² = BC²+AC²-2(BC)(AC)cos m<C

Substitute the given values

AB² = 70²+40²-2(70)(40)cos 64

AB² = 4900+1600-5600cos64

AB² = 6500-5600(0.4384)

AB² = 6500-2,454.87

AB² = 4,045.12

AB = √4,045.12

AB = 63.6mm

Hence the length of AB is 63.6mm

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Answer: The sequence is geometric

Step-by-step explanation:

In an arithmetic sequence, the consecutive terms differ by a common difference and this difference is linear.

Common difference = given term - the term before it

In geometric progression, the consecutive terms differ by a common ratio this difference is exponential.

Common ratio = given term/the term before it

Looking at the given sequence,

1) d = 6 - - 2 is not equal to - 18 - 6

Therefore, it is not an arithmetic sequence

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3 years ago
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castortr0y [4]
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2 years ago
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7 0
3 years ago
Read 2 more answers
Help pleaseeeeeeeeeeee
Yuliya22 [10]

Answer:

x = 1

GF = 12

GH = 15

FH = 3

Step-by-step explanation:

G___F___H

GH = GF + FH

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