Answer:
96 in^2
Step-by-step explanation:
area of rectangle: 24*8=192
Area of triangle: (1/2)*base*height
= .5 * 8 * 24
=192/2
=96
area of shaded=rectangle - triangle
= 192-96
which is also just 192/2
so it is 96
ummmm it could be third one i guesss
Answer:
I dont understand
Step-by-step explanation:
What is it you need help with?
1500 members have a contributor membership.
64.8% of the noncontributory memberships are individual memberships.
<u>Step-by-step explanation:</u>
There are 20,000 members of a zoo.
⇒ Total members = 20,000
From the graph shown,
7.5% of the members have a contributor membership.
<u>To find the number of members who have contributor membership :</u>
⇒ 7.5% of 20,000
⇒ (7.5/100) × 20,000
⇒ 7.5 × 200
⇒ 1500 members.
Therefore, 1500 members have a contributor membership.
<u>To find the percentage of the noncontributory memberships are individual memberships :</u>
The percentage of noncontributory memberships = 100% - 7.5% ⇒ 92.5%
The percentage of individual memberships = 60%
∴ What percentage of the noncontributory memberships are individual memberships ⇒ (60 / 92.5) × 100 = 64.8%
Answer:
The value is 
Step-by-step explanation:
From the question we are told that
The population proportion is 
The sample size is n = 563
Generally the population mean of the sampling distribution is mathematically represented as
Generally the standard deviation of the sampling distribution is mathematically evaluated as
=> 
=> 
Generally the probability that the proportion of persons with a college degree will differ from the population proportion by less than 5% is mathematically represented as
Here 
is the sample proportion of persons with a college degree.
So
![P( - (0.05 - 0.52 ) < \^ p < (0.05 + 0.52 )) = P(\frac{[[0.05 -0.52]]- 0.52}{0.02106} < \frac{[\^p - p] - p}{\sigma } < \frac{[[0.05 -0.52]] + 0.52}{0.02106} )](https://tex.z-dn.net/?f=P%28%20-%20%280.05%20-%200.52%20%29%20%3C%20%20%5C%5E%20p%20%3C%20%20%280.05%20%2B%200.52%20%29%29%20%3D%20P%28%5Cfrac%7B%5B%5B0.05%20-0.52%5D%5D-%200.52%7D%7B0.02106%7D%20%3C%20%5Cfrac%7B%5B%5C%5Ep%20-%20p%5D%20-%20p%7D%7B%5Csigma%20%7D%20%20%3C%20%5Cfrac%7B%5B%5B0.05%20-0.52%5D%5D%20%2B%200.52%7D%7B0.02106%7D%20%29)
Here
![\frac{[\^p - p] - p}{\sigma } = Z (The\ standardized \ value \ of\ (\^ p - p))](https://tex.z-dn.net/?f=%5Cfrac%7B%5B%5C%5Ep%20-%20p%5D%20-%20p%7D%7B%5Csigma%20%7D%20%20%3D%20Z%20%28The%5C%20standardized%20%5C%20%20value%20%5C%20%20of%5C%20%20%28%5C%5E%20p%20-%20p%29%29)
=> ![P( - (0.05 - 0.52 ) < \^ p < (0.05 + 0.52 )) = P[\frac{-0.47 - 0.52}{0.02106 } < Z < \frac{-0.47 + 0.52}{0.02106 }]](https://tex.z-dn.net/?f=P%28%20-%20%280.05%20-%200.52%20%29%20%3C%20%20%5C%5E%20p%20%3C%20%20%280.05%20%2B%200.52%20%29%29%20%3D%20P%5B%5Cfrac%7B-0.47%20-%200.52%7D%7B0.02106%20%7D%20%20%3C%20%20Z%20%20%3C%20%5Cfrac%7B-0.47%20%2B%200.52%7D%7B0.02106%20%7D%5D)
=> ![P( - (0.05 - 0.52 ) < \^ p < (0.05 + 0.52 )) = P[ -2.37 < Z < 2.37 ]](https://tex.z-dn.net/?f=P%28%20-%20%280.05%20-%200.52%20%29%20%3C%20%20%5C%5E%20p%20%3C%20%20%280.05%20%2B%200.52%20%29%29%20%3D%20P%5B%20-2.37%20%3C%20%20Z%20%20%3C%202.37%20%5D)
=> 
From the z-table the probability of (Z < 2.37 ) and (Z < -2.37 ) is
and
So
=>
=>
=>
