I believe that the mean is 6
The volume of a sphere, V = (4/3)(PI)(R^3)
Let k = (4/3)(PI)
Therefore, V = k (R^3)
Let R’ = new radius = 2R
V’ =k (R’^3)
= k (2R)^3
= 8 k R^3
= 8 V
The volume would be eight time the original volume.
Answer:
C. It would be shifted up.
Step-by-step explanation:
We base it off the y-intercept. Since -7 is <em>less</em><em> </em><em>than</em><em> </em>1, and our new function has a positive y-intercept, it would indeed be shifted up.
I am joyous to assist you anytime.
The answer to your question is 11
