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wolverine [178]
3 years ago
13

Pls answer enclosed questions :))

Mathematics
2 answers:
Rudiy273 years ago
7 0

Answer:

a) 9a + 6b

b) 5c - 3d

Step-by-step explanation:

a)

4a + 7b + 5a - b =

= 4a + 5a + 7b - 1b

= 9a + 6b

b)

6c + 4d - c - 7d =

= 6c - 1c + 4d - 7d

= 5c - 3d

Vsevolod [243]3 years ago
4 0
A) 9a+6b
b)5c-3d
combine like terms*
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Formula for pressure and volume
Alecsey [184]

The equations describing these laws are special cases of the ideal gas law, PV = nRT, where P is the pressure of the gas, V is its volume, n is the number of moles of the gas, T is its kelvin temperature, and R is the ideal (universal) gas constant.
8 0
4 years ago
The dimensions of an ancient Egyptian rug are 6 feet by 8 feet. Priscilla is creating a drawing of the rug with the scale 4 cm =
Taya2010 [7]

Answer:

12 x 18 CM.

Step-by-step explanation:

Because 3 cm is 1 ft  so if it is 4 you multiply that by 3 which equals 12 , and for 6 feet you multiply that by 3 cm  and get 18. SO it is 12 x 18 cm.

4 0
3 years ago
a plane flies 5.0km due north from a point O and then 6.0km on a bearing of 060° the pilot then changes course on a bearing of 1
Virty [35]

The plane flies a distance of approximately 10.536 kilometers in <em>straight</em> line and with a bearing of approximately 035°.

A plane that travels a distance r, in kilometers, with a bearing of \theta sexagesimal degrees can be represented in standard position by means of the following expression:

\vec r = r\cdot (\sin\theta, \cos \theta) (1)

We can obtain the resulting vector (\vec R) by the principle of superposition:

\vec R = \Sigma_{i=1}^{n} [r_{i}\cdot (\sin \theta_{i}, \cos \theta_{i})] (2)

If we know that r_{1} = 5\,km, \theta_{1} = 0^{\circ}, r_{2} = 6\,km, \theta_{2} = 60^{\circ}, r_{3} = 4\,km and \theta_{3} = 120^{\circ}, then the resulting vector is:

\vec R = 5\cdot (\sin 0^{\circ}, \cos 0^{\circ}) + 6\cdot (\sin 60^{\circ}, \cos 60^{\circ}) + 4\cdot (\sin 120^{\circ}, \cos 120^{\circ})

\vec R = (5\sqrt{3}, 6) \,[km]

The magnitude of the resultant is found by Pythagorean theorem:

\|\vec R\| = \sqrt{R_{x}^{2}+R_{y}^{2}}

And the bearing is determined by the following <em>inverse</em> trigonometric relationship:

\theta_{R} = \tan^{-1} \left(\frac{R_{y}}{R_{x}}\right) (3)

If we know that R_{x} = 5\sqrt{3}\,km and R_{y} = 6\,km, then the magnitude and the bearing of the resultant is:

\|\vec R\| = \sqrt{(5\sqrt{3})^{2}+6^{2}}

\|\vec R\| \approx 10.536\,km

\theta_{R} = \tan^{-1} \left(\frac{6}{5\sqrt{3}} \right)

\theta_{R} \approx 34.715^{\circ}

The plane flies a distance of approximately 10.536 kilometers in <em>straight</em> line and with a bearing of approximately 035°.

To learn more on vectors, we kindly invite to check this verified question: brainly.com/question/21925479

6 0
3 years ago
Stacey wishes to make a hamburger which is lower in fat without having to give up the great taste. She purchases 5 pounds of gro
STALIN [3.7K]

Answer:

%P = 8%

the percentage of fat in the mixture is 8%

Step-by-step explanation:

Given;

The percentage of fat in the mixture is;

%P = total mass of fat in mixture/total mass of mixture × 100%

%P = F/T × 100% ….....1

Mass of fat in mixture is;

She purchases 5 pounds of ground beef which is 15% fat

F1 = 15% of 5 pounds = 0.15×5 pounds

F1 = 0.75 pound

and combines it with 7 pounds of ground turkey which is only 3% fat

F2 = 3% of 7 pounds = 0.03 × 7

F2 = 0.21 pound

Total mass F = F1 + F2

F = 0.75+0.21

F = 0.96 pound

Total mass of mixture T = 5 + 7 pounds

T = 12 pounds.

From equation 1,

%P = F/T × 100%

%P = 0.96/12 × 100%

%P = 0.08×100%

%P = 8%

the percentage of fat in the mixture is 8%

5 0
4 years ago
(Geometry) PLZ HELP ASAP
katen-ka-za [31]

Answer:66.4

Step-by-step explanation:

A_{semicircle} =\frac{1}{2}  \pi r^2=\frac{1}{2}  \pi (\frac{13}{2} )^2= 66.36614 \approx66.4

8 0
3 years ago
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