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3 years ago

PLEASE HELP THIS IS DUE TODAY!!

1 answer:

7 0

while excluding 0, the product and quotient is positive if operating between same sign, otherwise if we operating different sign will resulted negative.

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Put the following equation of a line into slope-intercept form, simplifying all

Alex787 [66]

Answer:

y=(x/2)+5

Step-by-step explanation:

Slope-intercept form is y=mx+b where m is the slope and b is the y-intercept form. To get that, we need y by itself so we have to add 3x to both sides: 6y=30+3x. Now we divide by 6 and rearrange the right side: y=(3x+30)/6.

y = (3x/6)+(30/6) => y = (x/2)+5. We also know that the slope is 1/2 and the y-intercept is 5 because of the slope-intercept equation.

8 0

3 years ago

A scientist used 786 milliliters of a liquid for an experiment. How many liters of the liquid did the scientist use for this exp

Virty [35]

The answer is d , i hope this helps !

8 0

3 years ago

Read 2 more answers

From triangle PQR is P = 90°, PQ = 15.5 dm and PR = 11,7 dm. Calculate QR in dm. Round to one decimal.

Irina18 [472]

Answer:

QR = 19.4

Step-by-step explanation:

Use Pythagoras because p = 90°

Qr is hypotenuse

; (15.5)² + (11.7)²

= 377.14

√377.14

= 19.42009

= 19.42

= 19.4

hope it helps ☺️

4 0

3 years ago

Determine the value of x for which a || b if m<30=80-x and m<7=90-2x.

abruzzese [7]

D. 10

m<3 = 80 - (10) = 70
m<7 = 90 - (20) = 70

8 0

3 years ago

ahmed is sitting on a dock watching a float plane in a harbour. At a certain time, the plane is 350 m above the water and 470 m

Pavel [41]

Answer:

The angle of elevation of the plane measured from Ahmed is approximately 36.67°

Step-by-step explanation:

The given parameters of the float plane are;

The height of the float plane above the water, y = 350 m

The horizontal distance of the float plane from Ahmed, x = 470 m

Given that Ahmed is sitting on the dock, by the water, by trigonometric ratios, we have;

The height of the float plane, the distance of the plane from Ahmed and the line of sight forming the angle of elevation of the plane measured from Ahmed, form a right triangle

$tan\angle X = \dfrac{Opposite \ leg \ length}{Adjacent \ Leg\ length}$

Therefore

$tan(\theta) = \dfrac{y}{x}$

Where;

θ = The angle of elevation of the plane measured from Ahmed

y = The leg of the right triangle opposite the reference angle

x = The leg of the right adjacent to reference angle

Therefore;

θ = arctan(y/x) which gives;

θ = arctan(350/470) ≈ 36.67°

The angle of elevation of the plane measured from Ahmed, θ ≈ 36.67°.

8 0

3 years ago