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3 years ago

A right triangle has one angle that measures 83º. What is the measure of the other acute angle?

Mathematics

1 answer:

Nadusha1986 [10]3 years ago

7 0

180-(83+90)=180-173=7

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Fofino [41]

Answer:

Step-by-step explanation:......

5 0

3 years ago

The space shuttle travels at 28,000 km per hour. Using that information, estimate how many hours it will take the shuttle to rea

spayn [35]

Subtract the distance of the Earth from the sun from the distance of Saturn from the sun to find the distance from Earth to Saturn:

1,424,000,000 - 149,600,000 = 1,274,400,000 km ( Saturn from Earth)

Divide the distance by the speed to find the time:

1,274,400,000 km / 28,000 km per hour = 45,514.2857 hours.

Round to 45,514 hours.

3 0

3 years ago

Find an expression equivalent to the one shown below.

liberstina [14]

Answer:

I believe it would be A. 1

Step-by-step explanation:

$(8^{3} )^{9}$ ÷ $8^{27}$ = 1

hope this helps

7 0

3 years ago

Professor Liu gave the same quiz to the students in her morning class and in her afternoon class. The average (arithmetic mean)

natka813 [3]

Answer:

Afternoon class has more students.

Step-by-step explanation:

Let m be the number of students in the morning class and n be the number of students in the afternoon class.

The average score for the students in the morning class was 80, then the sum of their scores is $80m.$

The average score for the students in the afternoon class was 86, then the sum of their scores is $86n.$

The sum of the scores of both classes is

$80m+86n$

and the average score is

$\dfrac{80m+86n}{m+n}$

The average (arithmetic mean) score for the two classes combined was 84, then

$\dfrac{80m+86n}{m+n}=84\\ \\ 80m+86n=84m+84n\\ \\86n-84n=84m-80m\\ \\2n=4m\\ \\n=2m$

This means n is greater, so afternoon class has more students.

7 0

3 years ago

Every day a factory produces 5000 light bulbs, of which 2500 are type 1 and 2500 are type 2. if a sample of 40 light bulbs is se

alisha [4.7K]

<span>The solution: = 40, p = q = 0.5 P[x] = nCx *p^x *q^(n-x) when p = q = 0.5, the formula simplifies to P[x] = nCx/2^n = 40Cx/2^40 at least 18 of each type means 18 to 22 of (say) type I P(18 <= X <= 22) = 0.5704095 <------- qb mean = 40*0.5 = 20 SD = sqrt(npq) = sqrt(40*0.5*0.5) = 3.1623 z1= (18-20)/3.1623 = -0.63 , z2 = (22-20)/3.1623 = 0.63 P(-0.63 < z < 0.63) = 0.4713 <-------</span>

5 0

3 years ago