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3 years ago

Can someone help me please

Mathematics

2 answers:

Valentin [98]3 years ago

5 0

-4 and 4
hope this helps !

Leokris [45]3 years ago

5 0

3x^2 = 48

Divide both sides by 3

3x^2 ÷ 3 = 48 ÷ 3

x^2 = 16

Take a square root from both sides

√x^2 = + √16 " OR " √x^2 = - √16

x = 4 " OR " x = - 4

Thus the correct answer is option 3 .

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A garden is 90 m long and 75 m broad. A path 5 m wide is to be built outside and around it. Find the area of the path.also find

tensa zangetsu [6.8K]

Answer:

Step-by-step explanation:

Area of garden = length * breadth = 90 * 75 = 6750 Sq . m

= 6750 / 1000 = 0.675 hectare

Area of path = 100 * 85 - 90 * 75

= 8500 - 6750 = 1750 Sq. m

4 0

4 years ago

Anne can make 6 headbands 3/5 from meters of cloth. Which expression shows the amount of cloth needed to make 1 headband? What i

Marina CMI [18]

The amount of cloth needed to make 1 headband is 10 meters.

<h3>Unit value</h3>

Number of headbands Anne made = 6

Total clothes used = 3/5 meters

Cloth needed to make 1 headband = Number of headbands Anne made / Total clothes used

= 6 ÷ 3/5

= 6 × 5/3

= (6 × 5) / 3

= 30/3

= 10 meters

Therefore, the amount of cloth needed to make 1 headband is 10 meters.

Learn more about unit value:

brainly.com/question/14286952

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4 0

2 years ago

In the equation 6x – 2 = –4x + 2, Spencer claims that the first step is to add 4x to both sides. Jeremiah claims that the first

Sergeeva-Olga [200]

If you would like to know who is correct, you can find this using the following step:

<span>6x - 2 = -4x + 2

Spencer:
</span>6x - 2 = -4x + 2 /+4x
6x - 2 + 4x = -4x + 2 + 4x
10x - 2 = 2

Jeremiah:
6x - 2 = -4x + 2 /-6x
6x - 2 - 6x = -4x + 2 - 6x
-2 = -10x + 2

They both are correct. But in Jeremiah's version of solving the equation, we would have to multiply equation by -1 (or add 10x to both sides), which we don't have to do in the Spencer's version.

8 0

4 years ago

Read 2 more answers

Two machines are used for filling glass bottles with a soft-drink beverage. The filling process have known standard deviations s

stellarik [79]

Answer:

a. We reject the null hypothesis at the significance level of 0.05

b. The p-value is zero for practical applications

c. (-0.0225, -0.0375)

Step-by-step explanation:

Let the bottles from machine 1 be the first population and the bottles from machine 2 be the second population.

Then we have $n_{1} = 25$ , $\bar{x}_{1} = 2.04$ , $\sigma_{1} = 0.010$ and $n_{2} = 20$ , $\bar{x}_{2} = 2.07$ , $\sigma_{2} = 0.015$ . The pooled estimate is given by

$\sigma_{p}^{2} = \frac{(n_{1}-1)\sigma_{1}^{2}+(n_{2}-1)\sigma_{2}^{2}}{n_{1}+n_{2}-2} = \frac{(25-1)(0.010)^{2}+(20-1)(0.015)^{2}}{25+20-2} = 0.0001552$

a. We want to test $H_{0}: \mu_{1}-\mu_{2} = 0$ vs $H_{1}: \mu_{1}-\mu_{2} \neq 0$ (two-tailed alternative).

The test statistic is $T = \frac{\bar{x}_{1} - \bar{x}_{2}-0}{S_{p}\sqrt{1/n_{1}+1/n_{2}}}$ and the observed value is $t_{0} = \frac{2.04 - 2.07}{(0.01246)(0.3)} = -8.0257$ . T has a Student's t distribution with 20 + 25 - 2 = 43 df.

The rejection region is given by RR = {t | t < -2.0167 or t > 2.0167} where -2.0167 and 2.0167 are the 2.5th and 97.5th quantiles of the Student's t distribution with 43 df respectively. Because the observed value $t_{0}$ falls inside RR, we reject the null hypothesis at the significance level of 0.05