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Natalija [7]
3 years ago
13

What is the answer to this math problem with full work advanced geometry

Advanced Placement (AP)
1 answer:
Alisiya [41]3 years ago
6 0

Answer:

Chord UV = 5

Explanation:

Recall that Theorem of congruent chords relating to their arcs states that the intercepted arcs of two chords are congruent if the two chords are of the same length.

The converse of this theorem states that if two intercepted arcs of two corresponding chords are congruent, then the two chords are congruent to each other.

Let's apply the converse of this theorem to the problem given.

We are given that the intercepted arcs of chord UV and chord UT are 34° each.

Therefore, chord UV must be congruent to chord UT.

Since chord UT = 5

Therefore, chord UV = 5

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The mean for the total cost of the two items is 82. The standard deviation of the total cost of the two items is 14.14214. The probability of finding two random items at this auction with a total price of less than $80 is 0.44377.

<h3>What is a random variable?</h3>

A random variable is a variable with an undetermined value that gives values to each of the results of a statistical experiment.

From the parameters given:

  • Let us assume that X represents the random variable that connotes the price of the item during the large auction.

Given that:

  • X is normally distributed with a mean of $41 and
  • A standard deviation of $10

X \sim N(μ, σ²)

X \sim N(41, 10²)

Suppose we made an assumption that Y should denote the total cost of items:

i.e.

Y = X₁ + X₂

Here;

\mathbf{X_i \sim N(41, 10^2)} \\ \\ \mathbf{E(Y) = E(X_1+X_2) } \\ \\ \mathbf{E(Y) = 41 + 41 } \\ \\  \mathbf{E(Y) = 82}

The variance of (Y) is:

\mathbf{Var (Y) = Var(X_1+X_2) = Var (X_1) + Var(X_2) } \\ \\\mathbf{= 10^2+ 10^2} \\ \\ \mathbf{=200}

\mathbf{Standard \ deviation \ SD (Y) = \sqrt{200} }

= 14.14214

The probability of finding the two random items at the auction with a total price of less than $80 can be computed as:

P(Y < 80)  

Since the data is normally distributed,

\mathbf{=P\Big(Z < \dfrac{x -\mu}{\sigma}\Big)}

\mathbf{=P\Big(Z < \dfrac{80 -82}{14.14214}\Big)}

\mathbf{=P\Big(Z < -0.1414213\Big)}

Recall that:

P(Z < -z) = P(Z > z)

Hence;

= P (Z  > 0.1414213)

= 1 - P(Z ≤  0.1414213)

From the Z tables, the value of Z at 0.1414213 is 0.55623;

=  1 -  0.55623

= 0.44377

Therefore, we can conclude that the probability of finding two random items at this auction with a total price of less than $80 is 0.44377.

Learn more about random variables in probability here:

brainly.com/question/15246027

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