The product of multiplying the ones digit of 59 by 853 is 7677 and the product of multiplying the tens digit of 59 by 853 is 42650 and the final product is 50327
<h3>How to determine the product of the numbers?</h3>
The numbers are given as
853 and 59
By using the standard algorithm i.e. the partial product method, we have the following equation
853 * 59 = 853 * (50 + 9)
Open the bracket
So, we have
853 * 59 = 853 * 50 + 853 * 9
Evaluate the products
So, we have
853 * 59 = 42650 + 7677
The above means that the product of multiplying the ones digit of 59 by 853 is 7677 and the product of multiplying the tens digit of 59 by 853 is 42650
Next, we evaluate the sum
853 * 59 = 50327
This means that the final product is 50327
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Answer:
Step-by-step explanation:
8z (3x^2 +y)
The answer to your question is most likely A
So, here you have to look at the periodic table and see what the molar mass of each molecule composing the water compound

its two hydrogen atom plus an oxygen molecule, making it about 18g per mol.
That said, looking at the mass, we have to ask ourselves, if a mol of water contains 18g of mass, how many moles do we have in 0.5g of water?
We just do a cross multiplication:
Answer:
Step-by-step explanation:
Vertically opposite angles are equal.
8y + 36 = 14y -24 Subtract 36 to both sides
8y = 14y - 24 - 36 Combine
8y = 14y - 60 Subtract 14y from both sides
8y - 14y = - 60
-6y = -60 Divide by - 6
-6y/-6 = -60/-6
y = 10
===========================
x +48 = 64 Subtract 48 from both sides
x +48 - 48 = 64-16
x = 16