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garik1379 [7]
3 years ago
7

30 POINTS

Mathematics
2 answers:
Debora [2.8K]3 years ago
4 0

Answer:

Step-by-step explanation:

If we are looking for the probability that the battery lasts between 7 and 8 years, we find the z-score for the probability that it lasts less than 8 years, and then subtract from it the z-score for the probability that it lasts less than 7 years. This subtraction will give you what's left: the span in between 7 and 8 years. To find the z-score:

z=\frac{x_i-\mu}{\sigma} Therefore,

P(x < 8) has a z-score of

z=\frac{8-5}{1.2}=1.667 The p-value that accompanies this z-score is .99379 (which translates to 99.379% of the data falling below 8 years) and

P(x < 7) has a z-score of

z=\frac{7-5}{1.2}=2.5 The p-value that accompanies this z-score is .95224 (which translates to 95.224% of the data falling below 7 years).

Subtract the p-value of 2.5 from the p-value of 1.667 to get

.99379 - .95224 = .04155 = 4.16%, choice A.

kupik [55]3 years ago
3 0

Answer:

3.61%

Step-by-step explanation:

Mathematics, calculator

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Read 2 more answers
Can someone help me
defon
Answer for problem 46 is choice A
Answer for problem 47 is choice B
Answer for problem 48 is choice E

-----------------------------------------------------------------------------
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Work Shown

Problem 46
Equation 1: 3x+y = 17
Equation 2: x+3y = -1
Add equation 1 to equation 2 to get 4x+4y = 16. Divide every term by 4 to get x+y = 4. Then finally multiply both sides by 3 to get 3x+3y = 12
That shows why the answer is choice A

---------------------------------
Problem 47)

If y hours pass by, then y-(2/3)y=y/3 is the time value (2/3)y hours ago

So,
Distance = rate*time
d = r*t
d = x*(y/3)
d = (xy)/3
That's why the answer is choice B

---------------------------------
Problem 48)
Let L1,L2,L3 be the three lists where
L1 = {a1,a2,a3,...,ak} there are k scores here
L2 = {a1,a2,...,a10} there are 10 scores here
L3 = {a11,a12,...,ak} the remaining k-10 scores
S(L1) = sum of the scores in list L1
M(L1) = mean of L1 = 20 = S(L1)/k
M(L2) = mean of L2 = 15 = S(L2)/10
S(L1) = 20k
S(L2) = 150
S(L1) = S(L2)+S(L3)
M(L1) = [S(L2)+S(L3)]/k
20 = [150+S(L3)]/k
20k = 150+S(L3)
S(L3) = 20k-150
M(L3) = [S(L3)]/(k-10)
M(L3) = (20k-150)/(k-10)
So that shows why the answer is choice E
3 0
4 years ago
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