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Dmitry_Shevchenko [17]

3 years ago

15

There are20 keys on a keychain. One of the keys starts a car. If a key is randomly chosen what is the probability that it starts

the car
A)5% B)25% C)20% D)15%

1 answer:

pogonyaev3 years ago

7 0

The answer is 5%........

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The sum of a number and 3 divided by 9

polet [3.4K]

Answer:

$\frac{(x+3)}{9}$

Step-by-step explanation:

6 0

2 years ago

Line GH contains points (-2,6) and H (5,-3). What is the slope of GH

svetlana [45]

Answer:

-9/7

Step-by-step explanation:

To find the slope given 2 points, we use the formula

m = (y2-y1)/(x2-x1)

where (x1,y2) and (x2,y2) are the two points

m = (-3-6)/(5--2)

m = (-3-6)/(5+2)

= -9/7

8 0

3 years ago

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Find the distance between the points (-13,13) and (7,17)

Mazyrski [523]

Answer: 6√2

Decimal Form:

8.48528137

Step-by-step explanation:

6 0

2 years ago

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Find the gradient and the intercept shown by the straight line 2x + 3y = 6

sveta [45]

Answer:

$\sf gradient =\dfrac{-2}{3}\\\\ y -intercept = 2$

Step-by-step explanation:

<h2>Equation of the line in slope intercept form:</h2>

$\sf \boxed{\bf y = mx +b}$

Here m is the slope or gradient and b is the y-intercept.

Write the given equation in slope-intercept form.

2x + 3y = 6

3y = -2x + 6

$\sf y =\dfrac{-2}{3}x +\dfrac{6}{3}\\\\ y = \dfrac{-2}{3}x + 2$

$\sf gradient =\dfrac{-2}{3}\\\\ y -intercept = 2$

6 0

1 year ago

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A small business owner estimates his mean daily profit as $970 with a standard deviation of $129. His shop is open 102 days a ye

Katena32 [7]

Answer:

The probability that the shopkeeper's annual profit will not exceed $100,000 is 0.2090.

Step-by-step explanation:

According to the Central Limit Theorem if we have a population with mean <em>μ</em> and standard deviation <em>σ</em> and we select appropriately huge random samples (<em>n</em> ≥ 30) from the population with replacement, then the distribution of the sum of values of <em>X</em>, i.e ∑<em>X</em>, will be approximately normally distributed.

Then, the mean of the distribution of the sum of values of X is given by,

$\mu_{x}=n\mu$

And the standard deviation of the distribution of the sum of values of X is given by,

$\sigma_{x}=\sqrt{n}\sigma$

The information provided is:

<em>μ</em> = $970

<em>σ</em> = $129

<em>n</em> = 102

Since the sample size is quite large, i.e. <em>n</em> = 102 > 30, the Central Limit Theorem can be used to approximate the distribution of the shopkeeper's annual profit.

Then,

$\sum X\sim N(\mu_{x}=98940,\ \sigma_{x}=1302.84)$

Compute the probability that the shopkeeper's annual profit will not exceed $100,000 as follows:

$P (\sum X \leq 100,000) =P(\frac{\sum X-\mu_{x}}{\sigma_{x}}$

$=P(Z$

*Use a <em>z</em>-table for the probability.

Thus, the probability that the shopkeeper's annual profit will not exceed $100,000 is 0.2090.

6 0

3 years ago