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BartSMP [9]
3 years ago
12

A 20 foot ladder rests against the top of a 15 foot building. How far does the ladder extend from the base of the wall and what

angle does the ladder make with the ground?

Mathematics
1 answer:
Nady [450]3 years ago
4 0
Look at the picture.

Calculate x using the Pythagorean theorem:
x^2+15^2=20^2 \\
x^2+225=400 \\
x^2=400-225 \\
x^2=175 \\
x=\sqrt{175} \\
x=\sqrt{25 \times 7} \\
x=5\sqrt{7} \\
x \approx 13.23

Calculate α using sine:
\sin \alpha =\frac{15}{20} \\
\sin \alpha= 0.7500 \\ \alpha \approx 49^\circ

The ladder extends approximately 13.23 feet (exactly: 5√7 feet) from the base of the wall and makes an approximately 49° angle with the ground.

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2 years ago
Simon has more money than Kande. if Simon gave Kande K20, they would have the same amount. While if Kande gave Simon $22, Simon
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Given parameters;

  Let us solve this problem step by step;

Let us represent Simon's money by S

Kande's money by K

  • Simon has more money than Kande

               S > K

  •  if Simon gave Kande K20, they would have the same amount;

 if Simon gives $20, his money will be  S - 20 lesser;

      When Kande receives $20, his money will increase to K + 20

                     S - 20  = K + 20   ------ (i)

  • While if Kande gave Simon $22, Simon would then have twice as much as Kande;

          if Kande gave Simon $22, his money will be K - 22

    Simon's money, S + 22;

                  S + 22  = 2(K - 22)    ------ (ii)

Now we have set up two equations, let us solve;

         S - 20  = K + 20  ---- i

         S + 22  = 2(K - 22)  ;       S + 22  = 2K - 44  ---- ii

So,      S - 20  = K + 20

          S + 22  = 2K - 44

subtract both equations;

               -20 - 22  = (k -2k)  + 64

                   -42  = -k + 64

                       k  = 106

Using equation i, let us find S;

            S - 20 = K + 20

             S - 20  = 106 + 20

              S = 106 + 20 + 20  = 146

Therefore, Kande has $106 and Simon has $146

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