Answer: (6x^4 - 15x^3 - 2x^2 - 10x - 4) ÷ (3x^2 + 2)
= (6x^4 - 15x^3 + 4x^2 - 6x^2 - 10x - 4) ÷ (3x^2 + 2)
= (6x^4 + 4x^2 - 15x^3 - 10x - 6x^2 - 4) ÷ (3x^2 + 2)
= 2x^2(3x^2 + 2) - 5x(3x^2 + 2) - 2(3x^2 + 2) ÷ (3x^2 + 2)
= (3x^2 + 2)(2x^2 - 5x - 2) ÷ (3x^2 + 2)
= 2x^2 - 5x - 2 Ans.
I hope this helped!!! NO HATE COMMENTS IF I WAS WRONG!!!
From the given figure, we observe that,
The relationship between the variables is,
As the number of sunny days increases, the number of lost umbrellas tends to decrease.
Hence, the correct option is C.
Because when the atoms in the liquid are coldthe squeeze altogeter and it makethembgo down and when ther hot the spread out and make them go up
2x + 3y = 3 y = 8 – 3x
we have 2 equations
first equations: <span>2x + 3y = 3 y
</span>the second equation: 3y = 8 – 3x => <span>8-3x=3y
</span><span>------------------------------------------------------------
2x+3y=3y</span>2x=3y-3y
2x=0
x=0
8-3x=3y
8-0=3y
8=3y
y=8/3
S={x=0 ; y=8/3 }
The total moment of inertia of the two disks will be I = 2.375 × 10-³ Kgm² welded together to form one unit.
<h3>What is moment of inertia?</h3>
Moment of inertia is the quantity expressing a body's tendency to resist angular acceleration, which is the sum of the products of the mass of each particle in the body with the square of its distance from the axis of rotation.
Using the formulas to calculate the moment of inertia of a solid cylinder:
I = ½MR²
Where;
I = moment (kgm²)
M = mass of object (Kg)
R = radius of object (m)
Total moment of inertia of the two disks is expressed as: I = I(1) + I(2)
That is;
I = ½M1R1 + ½M2R2
According to the provided information;
R1 = 2.50cm = 0.025m
M1 = 0.800kg
R2 = 5.00cm = 0.05m
M2 = 1.70kg
I = (½ × 0.800 × 0.025²) + (½ × 0.05² × 1.70)
I = (½ × 0.0005) + (½ × 0.00425)
I = (0.00025) + (0.002125)
I = 0.002375
I = 2.375 × 10-³ Kgm²
Hence The total moment of inertia of the two disks will be I = 2.375 × 10-³ Kgm² welded together to form one unit.
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