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3 years ago

4x + 5y = 30 5x + 3y = 31

Mathematics

2 answers:

yaroslaw [1]3 years ago

7 0

Answer:

x=5

y=2 true......

Step-by-step explanation:

.............

Natalka [10]3 years ago

6 0

Answer:

y=2

x=5

trust me its by calculator

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Solve the system by the substitution method. Show your work.<br> 2y - x = 5<br> x^2 + y^2 - 25 = 0

Elza [17]

2y - x = 5
x^2 + y^2 - 25 = 0

x = 2y - 5

(2y-5)^2 + y^2 - 25 = 0
(2y-5)(2y-5) + y^2 - 25 = 0
4y^2 - 20y + 25 + y^2 - 25 = 0
5y^2 - 20y = 0
y = 0 , y = 4

x = 2y - 5 , when y = 0
x = - 5

x = 2y - 5 , when y = 4
x = 8 - 5
x = 3

6 0

3 years ago

Round 428,213 to the nearest ten thousand

givi [52]

Answer:

Round 428,213 to the nearest ten thousand = 428,210

6 0

3 years ago

how much water must be added to a 9-liter solution that contains 3% extract on baneberry to get a solution that contains 2% extr

yuradex [85]

Answer:

Amount water added = 4.5 L

Step-by-step explanation:

Given:

Amount of solution = 9 L

Amount of bane-berry = 3% of 9 L = 0.27 L

Computation:

Assume;

Amount water added = x L

Total solution = 9+x L

New percentage of bane-berry = 0.27x100/(9+x)

2 = 0.27*100/(9+x)

x = 4.5 L

Amount water added = 4.5 L

6 0

3 years ago

Determine whether each expression is equivalent to 49^2t – 0.5.

vampirchik [111]

Answer:

None of the expression are equivalent to $49^{(2t - 0.5)}$

Step-by-step explanation:

Given

$49^{(2t - 0.5)}$

Required

Find its equivalents

We start by expanding the given expression

$49^{(2t - 0.5)}$

Expand 49

$(7^2)^{(2t - 0.5)}$

$7^2^{(2t - 0.5)}$

Using laws of indices: $(a^m)^n = a^{mn}$

$7^{(2*2t - 2*0.5)}$

$7^{(4t - 1)}$

This implies that; each of the following options A,B and C must be equivalent to $49^{(2t - 0.5)}$ or alternatively, $7^{(4t - 1)}$

A. $\frac{7^{2t}}{49^{0.5}}$

Using law of indices which states;

$a^{mn} = (a^m)^n$

Applying this law to the numerator; we have

$\frac{(7^{2})^{t}}{49^{0.5}}$

Expand expression in bracket

$\frac{(7 * 7)^{t}}{49^{0.5}}$

$\frac{49^{t}}{49^{0.5}}$

Also; Using law of indices which states;

$\frac{a^{m}}{a^n} = a^{m-n}$

$\frac{49^{t}}{49^{0.5}}$ becomes

$49^{t-0.5}}$

This is not equivalent to $49^{(2t - 0.5)}$

B. $\frac{49^{2t}}{7^{0.5}}$

Expand numerator

$\frac{(7*7)^{2t}}{7^{0.5}}$

$\frac{(7^2)^{2t}}{7^{0.5}}$

Using law of indices which states;

$(a^m)^n = a^{mn}$

Applying this law to the numerator; we have

$\frac{7^{2*2t}}{7^{0.5}}$

$\frac{7^{4t}}{7^{0.5}}$

Also; Using law of indices which states;

$\frac{a^{m}}{a^n} = a^{m-n}$

$\frac{7^{4t}}{7^{0.5}}$ = $7^{4t - 0.5}$

This is also not equivalent to $49^{(2t - 0.5)}$

C. $7^{2t}\ *\ 49^{0.5}$

$7^{2t}\ *\ (7^2)^{0.5}$

$7^{2t}\ *\ 7^{2*0.5}$

$7^{2t}\ *\ 7^{1}$

Using law of indices which states;

$a^m*a^n = a^{m+n}$

$7^{2t+ 1}$

This is also not equivalent to $49^{(2t - 0.5)}$

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4 years ago

What is 6/2(1+2)? Correct answers only please!!

kherson [118]

Answer:

your answer is 9

hope this helps xx

8 0

3 years ago

Read 2 more answers