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3 years ago

Absolute value to distance help asap

Mathematics

1 answer:

ra1l [238]3 years ago

3 0

Answer:

Its c, none of the above.

Step-by-step explanation:

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Help please please please please please please please please

Cerrena [4.2K]

Question 1= $7,620

Question 2 (a) $3,211

Question 2 (b) $9,828

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3 years ago

PLEASE HELP I GIVE THANKS

Sergio039 [100]

IT IS D!!!! i know because C stands for juice and your buying 2 of them and the 6 stands for the $6 for bagels, hope you get it right!

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3 years ago

Ted’s team score average of 23.5 points in 4 basketball games. Lauren's team scores an average of 75.5 points in the same 4 gam

Setler [38]

Answer:

Lauren has 52 more points than Ted.

Step-by-step explanation:

Ted- 23.5

Lauren- 75.5

75.5-23.5=52

5 0

3 years ago

Bill weighs 120 lbs and is gaining ten lbs each month. Phil weighs 150 lbs and is gaining four lbs each month. How many months w

vaieri [72.5K]

First, let's write two expressions, letting x= the number of months which have elapsed:

Bill: 120 + 10x
Phil: 150 + 4x

If we set them equal to each other, then solve for x, that will be the number of months where their weights equal each other:

120+10x = 150 + 4x [starting equation]
-120 -4x -120 -4x [ subtract 120 from both sides, and 4x from both sides, to isolate the term with the variable]

<u>6x</u> = <u>30</u> [divide both sides by 5]
5 5

x=6. They will weigh the same in six months.

5 0

3 years ago

Read 2 more answers

Two athletic teams play a series of games; the first team to win 4 games is declared the overall winner. Suppose that one of the

kodGreya [7K]

Answer:

p=0.7103 (4-game series)
p=0.6480 (2-game series)

Step-by-step explanation:

Let X be the random variable equal the the first 4 straight wins. An overall win for the stronger team implies a negative binomial function with the parameters n=4, p=0.6:

$P(X=4)={{i-1}\choose {4-1}}0.6^40.4^{i-4},\ i=4,5,6,7$

#We find probabilities for the different values of i:

$P(X=4)={3\choose 3}0.6^4=0.1296\\\\P(X=5)={4\choose 3}0.6^40.4^1=0.2074\\\\P(X=6)={5\choose 3}0.6^40.4^2=0.2074\\\\P(X=4)={6\choose 3}0.6^40.4^3=0.1659$

Hence, probability of the stronger team winning overall is:

$=P(X=4)+P(X=5)+P(X=6)+P(X=7)\\\\=0.7103$

#Define Y as the random variable for winning 2/3 games.:

$P(Y=2)={1\choose 1}0.6^2=0.3600\\\\P(Y=3)={2\choose3}0.6^20.4=0.2880\\\\P(win)=0.2880+0.3600=0.6480$

Hence, probability of the stronger team winning in 2 out 3 game series is 0.6480

The stronger team has a higher chance of winning in a 4-game series(0.7103>0.6480)

8 0

3 years ago