Answer:
The 80% confidence interval for the the population mean nitrate concentration is (0.144, 0.186).
Critical value t=1.318
Step-by-step explanation:
We have to calculate a 80% confidence interval for the mean.
The population standard deviation is not known, so we have to estimate it from the sample standard deviation and use a t-students distribution to calculate the critical value.
The sample mean is M=0.165.
The sample size is N=25.
When σ is not known, s divided by the square root of N is used as an estimate of σM:
![s_M=\dfrac{s}{\sqrt{N}}=\dfrac{0.078}{\sqrt{25}}=\dfrac{0.078}{5}=0.016](https://tex.z-dn.net/?f=s_M%3D%5Cdfrac%7Bs%7D%7B%5Csqrt%7BN%7D%7D%3D%5Cdfrac%7B0.078%7D%7B%5Csqrt%7B25%7D%7D%3D%5Cdfrac%7B0.078%7D%7B5%7D%3D0.016)
The degrees of freedom for this sample size are:
![df=n-1=25-1=24](https://tex.z-dn.net/?f=df%3Dn-1%3D25-1%3D24)
The t-value for a 80% confidence interval and 24 degrees of freedom is t=1.318.
The margin of error (MOE) can be calculated as:
Then, the lower and upper bounds of the confidence interval are:
![LL=M-t \cdot s_M = 0.165-0.021=0.144\\\\UL=M+t \cdot s_M = 0.165+0.021=0.186](https://tex.z-dn.net/?f=LL%3DM-t%20%5Ccdot%20s_M%20%3D%200.165-0.021%3D0.144%5C%5C%5C%5CUL%3DM%2Bt%20%5Ccdot%20s_M%20%3D%200.165%2B0.021%3D0.186)
The 80% confidence interval for the population mean nitrate concentration is (0.144, 0.186).
Answer:
x=24-1
x=9+1
Step-by-step explanation:
Hello the answer is of course 4,5,6
Answer: 6:18
All of the other options are equal to 1:3
A- positive
B-negative
C-positive
A was positive because 5-2 would be positive 3.
B was negative because 8-12 would be negative 4.
C was positive because -5+8 is positive 3.