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garri49 [273]
4 years ago
15

A student loses 3.4 lb in one month how many grams did she lost

Mathematics
1 answer:
PilotLPTM [1.2K]4 years ago
3 0
Approx. 1542 grams !
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find the square root of each of the following decimal numbers correct to two places of decimal : I. 175.01 II. 423.74 III. 5893.
netineya [11]

Answer:

i. 13.23

ii. 20.58

iii. 76.77

iv. 84.48

Step-by-step explanation:

Here , we are to calculate the square root of we have of the decimal numbers and correct to two decimal places.

i. √(175.01) = 13.229 = 13.23

ii. √(423.74) = 20.5849 = 20.58

iii. √(5893.27) = 76.767 = 76.77

iv. √(7136.8) = 84.4795 = 84.48

Kindly note that the approximation to two decimal places are the figures after the equal to

3 0
3 years ago
Identify the numbers that are located below -3.5 on a vertical number line.
Mumz [18]
The answers are: -5.3, -6.5
3 0
3 years ago
What are the solutions?<br>8x^2-12x-23=-5​
erastova [34]

Answer:

x = 3/4 + (3 sqrt(5))/4 or x = 3/4 - (3 sqrt(5))/4

Step-by-step explanation:

Solve for x over the real numbers:

8 x^2 - 12 x - 23 = -5

Divide both sides by 8:

x^2 - (3 x)/2 - 23/8 = -5/8

Add 23/8 to both sides:

x^2 - (3 x)/2 = 9/4

Add 9/16 to both sides:

x^2 - (3 x)/2 + 9/16 = 45/16

Write the left hand side as a square:

(x - 3/4)^2 = 45/16

Take the square root of both sides:

x - 3/4 = (3 sqrt(5))/4 or x - 3/4 = -(3 sqrt(5))/4

Add 3/4 to both sides:

x = 3/4 + (3 sqrt(5))/4 or x - 3/4 = -(3 sqrt(5))/4

Add 3/4 to both sides:

Answer:  x = 3/4 + (3 sqrt(5))/4 or x = 3/4 - (3 sqrt(5))/4

4 0
3 years ago
Select the correct answer from each drop-down menu
Ostrovityanka [42]

Answer:

Marcel's financial goal is to purchase a house. To make Marcel's financial goal of purchasing a house a specific goal, he can FOCUS ON SAVING FOR A DOWN PAYMENT. Next, Marcel can make his goal timely by GIVING HIMSELF A DEADLINE. Lastly, Marcel can make his financial goal measurable by TRACKING THE AMOUNT OF MONEY HE SAVES each month.

7 0
3 years ago
We are again studying the times required to solve two elementary math problems. Suppose we ask four students to attempt both Pro
KiRa [710]

Answer:

(-16.494 ; -3.506)

Step-by-step explanation:

student Prob A Prob B difference, d (A-B)

1 20 35____ - 15

2 30 40 ___ - 10

3 15 20 ___ - 5

4 40 50 __ - 10

Difference, d = -15, -10, -5, -10

Xd = Σd/ n = - 40 / 4 = - 10

Standard deviation of d ; Sd = 4.082

The confidence interval for the difference is given as :

Xd ± Tcritical*(Sd/√n)

Tcritical at 95%; df = n - 1 ; 4 - 1 = 3

Tcritical(0.05, 3)). = 3.182

C.I = -10 ± 3.182(4.082/√4)

C.I = -10 ± 6.494462

C. I = (-16.494 ; -3.506)

6 0
3 years ago
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