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3 years ago

7

Use the distributive property to expand this expression: 3(-3a + 4) =

1 answer:

mylen [45]3 years ago

4 0

Answer:

-9a+12

Step-by-step explanation:

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What is the value of x

timama [110]

Answer:

The answer to your question is: x = 27

Step-by-step explanation:

The are vertical angles, so they measure the same:

4x + 7 = 5(x - 4)

4x + 7 = 5x - 20 Expanding

4x - 5x = -20 - 7 Simplify like terms

-x = -27

x = 27

3 0

4 years ago

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A net of a square pyramid is shown. The total area of the pyramid's triangular faces is 80 cm'. What is the area of the pyramid'

ankoles [38]

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5 0

3 years ago

Solve for x ... x/6 = 2

hjlf

Answer:The answer is x=12

Step-by-step explanation: 2*6=12 and 12/6=2

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3 years ago

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Sam wants to know how long it will take to fill his baby pool that holds 24 gallons. After 1 minute, there are 2 gallons of wate

Alecsey [184]

I believe the x value is 12. so it is 12, 24

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4 years ago

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The initial size of the population is 300. After 1 day the population has grown to 800. Estimate the population after 6 days. (R

Cloud [144]

Solution :

Given initial population = 300

Final population after 1 day = 800

Number of days = 6

∴ $\frac{dP}{dt} =kt^{1/2}$

P(0) = 300 P(1) = 300

We need to find P(8).

$dP = kt^{1/2} dt$

$\int 1 dP = \int kt^{1/2} dt$

$P(t) = k \left(\frac{t^{3/2}}{3/2}\right)+c$

$P(t)= \frac{2k}{3}t^{3/2} + c$

When P(0) = 300

$300 = \frac{2k}{3} (0)^{3/2} + c$

∴ c = 300

∴ $P(t)= \frac{2k}{3}t^{3/2} + 300$

When P(1) = 800

$800 = \frac{2k}{3} (1)^{3/2} + 300$

$500 = \frac{2k}{3}$

∴ k = 750

$P(t)= 500t^{3/2} + 300$

So, P(8) is

$P(t)= 500(8)^{3/2} + 300$

= 11,614

So the population becomes 11,614 after 8 days.

8 0

3 years ago