Answer:
y = -4/3x - 1
Step-by-step explanation:
First, plug in 5 for x:
| -5 * 5 + 12 | = |-25 + 12| = |-13|
Those two lines are absolute value, which measures the distance from the number to 0 on a number line. This distance is always positive.
The distance from -13 to 0 on a number line is 13. The answer is 13.
Answer:
1+(3×u-1÷2u)=1+(5u÷2)=(2+5y)÷1
Answer:
![xy^3 \sqrt[4]{y^3}](https://tex.z-dn.net/?f=xy%5E3%20%5Csqrt%5B4%5D%7By%5E3%7D)
Step-by-step explanation:
Recall the exponent property
.
We can use this property to break the problem down:
![\sqrt[4]{x^4y^{15}}=\sqrt[4]{x\cdot x\cdot x\cdot x\cdot y^3\cdot y^3\cdot y^3\cdot y^3\cdot y^3}=\boxed{xy^3 \sqrt[4]{y^3}}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7Bx%5E4y%5E%7B15%7D%7D%3D%5Csqrt%5B4%5D%7Bx%5Ccdot%20x%5Ccdot%20x%5Ccdot%20x%5Ccdot%20y%5E3%5Ccdot%20y%5E3%5Ccdot%20y%5E3%5Ccdot%20y%5E3%5Ccdot%20y%5E3%7D%3D%5Cboxed%7Bxy%5E3%20%5Csqrt%5B4%5D%7By%5E3%7D%7D)
Answer: Whats the user?
Step-by-step explanation: