Triangle ABC is an isosceles triangle.
Solution:
Given data:
∠ABC = 70° and ∠ACD = 55°
<em>If two parallel lines are cut by a transversal, then alternate interior angles are congruent.</em>
m∠BAC = m∠ACD
m∠BAC = 55°
<em>Sum of the angles in a straight line add up to 180°.</em>
m∠ACD + m∠ACB + m∠ABC = 180°
55° + m∠ACB + 70° = 180°
m∠ACB + 125° = 180°
Subtract 125° from both sides, we get
m∠ACB = 55°
In triangle ABC,
∠BAC = 55° and ∠ACB = 55°
∠BAC = ∠ACB
Two angles in the triangle are equal.
Therefor triangle ABC is an isosceles triangle.
Answer:
16.907
Step-by-step explanation:
Okay, to answer this question,
<span>Perpendicular lines have slopes that are inverse of one another and with opposite signs so,
If a line has a slope of m= -2 than a perpendicular line will have slope m=1/2
If a line has a slope of m= -3/4 than a perpendicular line will have slope m=4/3
If a line has a slope of m= 6 than a perpendicular line will have slope m=-1/6
So, just find the slope of your line, using it, get the slope of the line that will be perpendicular and then just get the equation for a line that has that slope and passes through point (-2,3) using:
y - y1 = m(x - x1)
I hope I helped you with my answer</span>
n+29 is that what you mean
A: 2.5 pounds= 2.5
B: 2.5 pounds= 1.63
C: 2.5 pounds= 1.25
Lowest to highest is C, B, A
