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kap26 [50]
3 years ago
11

B) Simplify the expression (V7 + 3) square 2​

Mathematics
2 answers:
Sauron [17]3 years ago
7 0
V*7+3*v7+3 I’m not sure so I might be wrong
Ivahew [28]3 years ago
3 0

Answer:

49v^{2} +42v+9

Step-by-step explanation:

First, let me say, I'm not sure what exactly the equation is because it's worded weirdly, but I'm assuming it's (7v+3)^{2}.

(7v+3)(7v+3) [7v+3^{2} is the same as (7v+3)(7v+3).]

49v^{2}  +42v+9 [When you multiply them, this is the product.]

This is as far as you can simplify without knowing the value of v as far as I know.

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8,541.023 and 154340

Step-by-step explanation:


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24. If all of the dimensions of the aquarium
Zigmanuir [339]

Answer:

You can solve this problem by doubling each original measure then putting them in the equation. So, a length of 6in becomes 12in, a width of 10in becomes 20in, a height of 9in becomes 18in. The equation is now 12x20x18. 12x20= 240. 240x18= 4,320. This means the new aquarium has a volume of 4,320in3.

Step-by-step explanation:

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2 years ago
Given cos theta = - 2/5 and sin theta < 0, find the six trigonometric values. I need help with this
Lena [83]

Answer:

\sin\,\theta =-\frac{\sqrt{21} }{5}

\tan\,\theta =\frac{\sqrt{21} }{2}

\sec\,\theta = \frac{-5}{2}

cosec\,\theta =\frac{-5}{\sqrt{21} }

\cot\,\theta =\frac{2}{\sqrt{21} }

Step-by-step explanation:

\cos\theta =\frac{-2}{5}

As both sin\,\theta,

\theta lies in the third quadrant.

In the third quadrant,

\sin\theta

\sin\,\theta =-\sqrt{1-\cos^2\,\theta} \\=-\sqrt{1-(\frac{-2}{5})^2 } \\\\=-\sqrt{1-\frac{4}{25} }\\\\=-\sqrt{\frac{25-4}{25} }\\\\=-\frac{\sqrt{21} }{5}

\tan\,\theta = \frac{\sin\,\theta}{\cos\,\theta }\\\\=\frac{\frac{-\sqrt{21} }{5} }{\frac{-2}{5} }\\\\=\frac{\sqrt{21} }{2}

\sec\,\theta =\frac{1}{\cos\,\theta }\\\\=\frac{1}{\frac{-2}{5} }\\\\=\frac{-5}{2}

\ cosec \,\theta = \frac{1}{sin\,\theta }\\\\=\frac{1}{\frac{-\sqrt{21} }{5} }\\\\=\frac{-5}{\sqrt{21} }

\cot\,\theta =\frac{1}{\tan\,\theta}\\\\=\frac{1}{\frac{\sqrt{21} }{2} }\\\\=\frac{2}{\sqrt{21} }

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3 years ago
Which of the following sets of ordered pairs is not a function?
Ksenya-84 [330]

Answer:

is c simple

Step-by-step explanation:

because it is ok is simple if you tick wet my brain XD

3 0
2 years ago
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