Answer:
The ball traveled 116.25 m when it hit the ground for the fifth term
Step-by-step explanation:
This is a geometric progression exercise and what we are asked to look for is the sum of a GP.
The ball was dropped from a height of 60 m. This means that the initial height of the ball is 60 m.
First value, a = 60
Each time it hit the ground, it bounced up 1/2 (half) of the height that it dropped.
This is the common ratio, r = 1/2 = 0.5
The number of terms it hits the ground is the number of terms in the GP.
number of terms, n = 5
The distance traveled by the ball when it hit the ground for the fifth term will be modeled by the equation:

Answer:
Nobody likes a short, one-word-answer. Let’s make sure other people understand everything.
Step-by-step explanation:
By lisa Simpson
Answer:
To know which is better to pay.
Step-by-step explanation:
Good Luck
Answer:
(b) 1
Step-by-step explanation:
To differentiate
we will need the product rule:
.
We have
, so the following equation is true by the transitive property:

By subtraction property we have:

Since
, then we can divide both sides by
:


This implies
is constant.
So we have that
where
is a real number.
Since
and
, then by transitive property
.
So
.
Checking:


So the following conditions were met.
Answer:
PD = 12
Step-by-step explanation:
Using the tangent ratio in right Δ PDW and the exact value
tan30° =
, then
tan30° =
=
=
=
( cross- multiply )
PD = 12