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kondor19780726 [428]

2 years ago

15

Pleeeeeeeeeeeeeeeeeease help

1 answer:

IgorLugansk [536]2 years ago

8 0

Answer:

(-5/7)^17

Step-by-step explanation:

When multiplying numbers to a certain power, you will add the powers together. When dividing numbers to a certain power, you will subtract the powers.

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A ball was dropped from a height of 60m. Each time it hit the ground, it bounced up 1/2 (half) of the height that it dropped. Ho

asambeis [7]

Answer:

The ball traveled 116.25 m when it hit the ground for the fifth term

Step-by-step explanation:

This is a geometric progression exercise and what we are asked to look for is the sum of a GP.

The ball was dropped from a height of 60 m. This means that the initial height of the ball is 60 m.

First value, a = 60

Each time it hit the ground, it bounced up 1/2 (half) of the height that it dropped.

This is the common ratio, r = 1/2 = 0.5

The number of terms it hits the ground is the number of terms in the GP.

number of terms, n = 5

The distance traveled by the ball when it hit the ground for the fifth term will be modeled by the equation:

$S_n = \frac{a(1 - r^n) }{1 - r} \\S_5 = \frac{60(1 - 0.5^5) }{1 - 0.5}\\S_5 = \frac{58.125}{0.5} \\S_5 = 116.25 m$

4 0

3 years ago

What is the length of segment AB?<br> 7<br> 9<br> 18<br> 25

Usimov [2.4K]

Answer:

Nobody likes a short, one-word-answer. Let’s make sure other people understand everything.

Step-by-step explanation:

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5 0

2 years ago

What is the point of comparing prices?

kherson [118]

Answer:

To know which is better to pay.

Step-by-step explanation:

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6 0

2 years ago

Read 2 more answers

6. Let f and g be differentiable functions

Julli [10]

Answer:

(b) 1

Step-by-step explanation:

To differentiate $h(x)=f(x)g(x)$ we will need the product rule:

$h'(x)=f'(x)g(x)+f(x)g'(x)$ .

We have $h'(x)=f(x)g'(x)$ , so the following equation is true by the transitive property:

$f'(x)g(x)+f(x)g'(x)=f(x)g'(x)$

By subtraction property we have:

$f'(x)g(x)=0$

Since $g(x) \neq 0$ , then we can divide both sides by $g(x)$ :

$f'(x)=\frac{0}{g(x)}$

$f'(x)=0$

This implies $f(x)$ is constant.

So we have that $f(x)=c$ where $c$ is a real number.

Since $f(0)=1$ and $f(0)=c$ , then by transitive property $1=c$ .

So $f(x)=1$ .

Checking:

$h(x)=1 \cdot g(x)$

$h'(x)=g'(x)=1 \cdot g'(x)$

So the following conditions were met.

5 0

3 years ago

In the figure below, PDW and WTC are right triangles. The measure of WPD is 30°, the measure of WC is 6 units, the measure of WT

aliya0001 [1]

Answer:

PD = 12 $\sqrt{3}$

Step-by-step explanation:

Using the tangent ratio in right Δ PDW and the exact value

tan30° = $\frac{1}{\sqrt{3} }$ , then

tan30° = $\frac{opposite}{adjacent}$ = $\frac{WD}{PD}$ = $\frac{12}{PD}$ = $\frac{1}{\sqrt{3} }$ ( cross- multiply )

PD = 12 $\sqrt{3}$

4 0

2 years ago

Read 2 more answers