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mrs_skeptik [129]
3 years ago
7

Find the value of ccc so that the polynomial p(x)p(x)p, left parenthesis, x, right parenthesis is divisible by (x-4)(x−4)left pa

renthesis, x, minus, 4, right parenthesis. p(x) = cx^3-15x -68p(x)=cx 3 −15x−68
Mathematics
1 answer:
Elis [28]3 years ago
8 0

Answer:

<h3>c =2</h3>

Step-by-step explanation:

For the polynomial to be divisible by x-4, hence x = 4

Given

p(x) = cx^3-15x -68

p(4) = c4^3-15(4)-68

p(4) = 64c-128

If p(4) = 0

0= 64c - 128

64c = 128

c = 128/64

c = 2

hence the value of c is 2

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