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tiny-mole [99]
3 years ago
15

WILL GIVE BRAINLIEST!!!

Mathematics
2 answers:
timofeeve [1]3 years ago
4 0

Answer:

y=448-28x

Step-by-step explanation:

Let x be the number of miles.

We have been given that Sully's car has an average fuel economy of 28 miles per gallon. The capacity of the fuel tank is 16 gallons.

Let us find the number of miles that Sully can drive with 16 gallons.

\text{Number of miles Sully can drive}=\text{16 gallons}\times \frac{\text{28 miles}}{\text{gallon}}  

\text{Number of miles Sully can drive}=\text{16}\times \text{28 miles}  

\text{Number of miles Sully can drive}=448\text{ miles}  

This means that initially Sully's car has can drive 448 miles, so at x equals 0, y will be 448.

As the car consumes 1 gallon for each 28 miles driven, so the gallons of fuel consumed in traveling x miles will be 28x. As each gallon of fuel will decrease with each 28 miles traveled, so slope of our function will be -28.

Upon substituting slope and y-intercept in slope-intercept form (y=mx+b), we will get our function as:

y=448-28x

Therefore, our required function will be: y=448-28x.

LenKa [72]3 years ago
3 0
28 mpg times 16 gallons gives a max distance of 448 miles.
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Veronika [31]

Answer:

Step-by-step explanation:

√108 ÷ √125 + √75

= 6√3 ÷ 5√5 + 5√3

= 11√3 / 5√5

hope this helps

plz mark as brainliest!!!!!!!

4 0
3 years ago
1 - 2x = -x - 3 what is the answer?
cricket20 [7]
Isolate the variable x.
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4 0
3 years ago
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A paper is in the form of a rectangle ABCD in which AB= 18 cm and BC=14cm.A semicircular portion with BC as diameter is cut off.
svetoff [14.1K]

Answer:

remaining portion is area= area of rectangle- area of semicircle

= 18*14 - 3.14*7^2

=252-154.86

=199.86cm^2

7 0
3 years ago
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Kazeer [188]

Answer:

The solutions are given below:

Step-by-step explanation:

x(x-3)+4(x²+2)

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= x²+4x²+8-3x

= 5x²+8-3x

2(a+5)-3(a+7)

= 2a+10-3a-21

= 2a-3a+10-21

= -a-11

xy(x²yz-xy²z+xyz²)

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8 0
3 years ago
Read 2 more answers
Evaluate:
Anni [7]

Answer:

a) = 4.5

b) = 3.3

Step-by-step explanation:

Before solving our problems given to us let us under stand the rule of cube roots

It says \sqrt[3]{x \times x \times x} = x   -----(A)

Also

\sqrt[3]{x \times x \times x \times y \times y \times y} = x \times y   ---(B)

Now let us see each part one by one

a) we have

\sqrt[3]{64} + \sqrt[3]{0.027} + \sqrt[3]{0.008}

Now 64 = 4 x 4 x 4

0.027 = 0.3 x 0.3 x 0.3

0.008 = 0.2 x 0.2 x 0.2

substituting these values

\sqrt[3]{4 \times 4 \times 4} + \sqrt[3]{0.3 \times 0.3 \times 0.3} + \sqrt[3]{0.2 \times 0.2 \times 0.2}

Applying Rule A in above

=4+0.3+0.2

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b) we have \sqrt[3]{0.3 \times 0.3 \times 0.3 \times 11 \times 11 \times 11}

Applying the B rule in this

=0.3 \times 11

3.3

4 0
3 years ago
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