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3 years ago

13

At a local department store, pants have been reduced to $12. This price is at 75% of the original price for pants. Given this, w

hat was the original price of the pants?

1 answer:

goldfiish [28.3K]3 years ago

7 0

The original price of the pants were 48 dollars

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Choose 3 values that would make this inequality true 28 + x > 42

tester [92]

Answer:

100, 15, 24 I think that is it

Step-by-step explanation:

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2 years ago

Read 2 more answers

tracy goes and purchases school supplies she buys pens pencils folders and markers for $30.90, if the sales tax is 6% what is th

____ [38]

The tax is 1.85$ and total cost is 32.75$

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3 years ago

A fluid moves through a tube of length 1 meter and radius r=0.006±0.00025 meters under a pressure p=4⋅105±2000 pascals, at a rat

iris [78.8K]

Answer:

Maximum error for viscosity is 17.14%

Step-by-step explanation:

We know that everything is changing with respect to the time, "r" is changing with respect to the time, and also "p" just "v" will not change with the time according to the information given, so we can find the implicit derivative with respect to the time, and since

$n = (\frac{\pi}{8}) (\frac{pr^4}{v})\\$

The implicit derivative with respect to the time would be

$\frac{dn}{dt} = \frac{\pi}{8} ( \frac{r^4}{v} \frac{dp}{dt} + \frac{4pr^3}{v}\frac{dr}{dt} )$

If we multiply everything by dt we get

$dn = \frac{\pi}{8} ( \frac{r^4}{v} dp + \frac{4pr^3}{v} dr})$

Remember that the error is given by $\frac{dn}{n}$ therefore doing some algebra we get that

$\frac{dn}{n} = 4 \frac{dr}{r} + \frac{dp}{p}$

Since, r = 0.006 , dr = 0.00025 , p = 4*105 , dp = 2000 we get that

$\frac{dn}{n} = 0.1714$

Which means that the maximum error for viscosity is 17.14%.

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3 years ago

Solve each of the following equations for xx using the same technique as was used in the Opening Exercise.

Brrunno [24]

Answer:

The value of the x is 1/9.

Step-by-step explanation:

Data provided in the question is:

$3^2/x=81$

To find out:-

the value of x.

Solution for the equation:-

$3^2/x = 81\\9/x=81\\9/81=x\\1/9=x\\$

On solving the given question or equation by using mathematics of algebra we find out the value of x to be 1/9.

7 0

3 years ago

Hello, I am currently very stuck with this problem and I am unsure as to how I would solve it.

borishaifa [10]

We have the equation

$20y=x^2-10-15$

Let's complete the square, to do it let's add and subtract 25 on the right side

$\begin{gathered} 20y=x^2-10-15+25-25 \\ \\ 20y=(x-5)^2-15-25_{} \\ \\ 20y=(x-5)^2-40 \\ \\ \end{gathered}$

Now we can have y in function of x

$\begin{gathered} y=\frac{1}{20}(x-5)^2-2 \\ \\ \end{gathered}$

Now we can already identify the vertex because it's in the vertex form:

$y=a(x-h)+k$

Where the vertex is

$(h,k)$

As we can see, h = 5 and k = -2, then the vertex is

$(5,-2)$

Now we can continue and find the focus, the focus is

$\mleft(h,k+\frac{1}{4a}\mright)$

We have a = 1/20, therefore

$\begin{gathered} \mleft(5,-2+5\mright) \\ \\ (5,3) \end{gathered}$

The focus is

$(5,3)$

And the last one, the directrix, it's

$y=k-\frac{1}{4a}$

Then

$\begin{gathered} y=-2-5 \\ \\ y=-7 \end{gathered}$

Hence the correct answer is: vertex (5, -2); focus (5, 3); directrix y = -7

5 0

1 year ago