Answer: R(t) = 750 + 0.04t
Step-by-step explanation:
Here's the complete question:
Ebuka's monthly rent is $750. If Ebuka pays the rent late, his landlord charges 4% interest per week that the payment is late. Write a function that gives the total cost R(t), in dollars, of Ebuka's rent if he pays it t weeks late.
The above question will be represented by:
R(t) = $750 + (4% × t)
R(t) = 750 + (4/100 × t)
R(t) = 750 + 0.04t
If it is asking about what is 136x3 then that would be 816
Answer:
A
Step-by-step explanation:
theres 3 ( x³, -3x, 3)
240 inches cut into 2 equal pieces is just taking half of the wire.
Making the two pieces of wire 120 inches.
If you bend one 120 inch wire into a square, that means that each side equals 30 inches. (A square has 4 sides. 120/4 = 30)
An area of a square is length times width, which the length equals 30 and width equal to thirty. 30 * 30 = 900. square inches.
120 wire bent into a triangle makes each side equal to 40. 120/3=40. The area of an equilateral triangle is height times width. The width is just one of the sides (40 inches) but the height needs some geometry. To find the height you need to use either 30 times sin(60) or 30 times cos(30), both are equal. To be clear, I will leave the height as 30sin(60). The area will be equal to

which can be simply written as 1200sin(60).
So the sum of both areas is
Please refer to the figure attached for the diagram of this problem.
Steps needed to find the width of the field (CD):
First, we should note that angle d would be equal to 27 degrees because there are two parallel lines that are cut by a transversal. Furthermore, angle a would be equal to 5 degrees since we just need to subtract 27 from 32.
We then subtract 27 and 5 from 180 to get angle c.

. Angle c is therefore 148 degrees.
Next, we need to find angle e which is just the supplementary of angle c. Angle e therefore measures

degrees.
For the next step we use sine law to find the length of segment AC:


Lastly, we need to utilize the sine law again to find the length of segment CD or the width of the field:

ANSWER: The width of the field is 290 ft.