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3 years ago

Please help me please!!

Mathematics

1 answer:

Aleks04 [339]3 years ago

6 0

A because the line is only going through the graph and hitting each point once

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Which of the following best classifies a quadrilateral with coordinates A(2,6), B(5, 1), C(10, 4), and D(7,9)?

navik [9.2K]

Answer:

a rhombus

Step-by-step explanation:

If you graph the problem, you can see the shape of the quadrilateral. I attached a picture of a graph below. I hope this helped you!! Have a great rest of your day.

3 0

3 years ago

What is the slope of the line passing through (1, 2) and (3, 8)? A: slope = 1/7 B: slope = 1/3 C: slope = 3 D: slope = 7

Aliun [14]

Slope = (y2-y1)/(x2-x1) = (8-2)/(3-1) = 6/2 = 3. So the answer is c.

5 0

3 years ago

Read 2 more answers

B: Alex is 12 years older than George.

UkoKoshka [18]

Answer:

The ratio of George age to Carl's age is 1:12.

Step-by-step explanation:

Let the age of George be 'g'.

Let the age of Alex be 'a'.

Also Let the age of Carl be 'c'.

Given:

The sum of their ages is 68.

So equation can be framed as;

$g+a+c=68 \ \ \ \ equation 1$

Also Given:

Alex is 12 years older than George.

So equation can be framed as;

$a =g+12 \ \ \ \ equation \ 2$

Now Given:

Carl is three times older than Alex.

$c=3a$

But $a =g+12$

So we get;

$c = 3(g+12) \\\\c= 3g+36 \ \ \ \ equation \ 3$

Now Substituting equation 2 and equation 3 in equation 1 we get;

$g+a+c=68\\\\g+g+12+3g+36=68\\\\5g+48=68$

Subtracting both side by 48 using subtraction property of equality we get;

$5g+48-48=68-48\\\\5g=20$

Now Dividing both side by 5 using Division property of equality we get;

$\frac{5g}{5}=\frac{20}{5}\\\\g =4$

Hence George age $g = 4 \ years$

Now Alex age $a=g+12 = 4+12 =16\ years$

Also Carl's age $c=3g+36=3\times 4+36 =12+36 =48\ years$

Now we need to find the ratio of George age to Carl's age.

$\frac{g}{c}=\frac{4}{48} = \frac{1}{12}$

Hence the ratio of George age to Carl's age is 1:12.

3 0

3 years ago

I Need help! If you help me you'll get 10 points!!

natka813 [3]

To solve this problem you must apply the proccedure shown below:

1. You have that the number of innings are expressed as a mixed number in the exercise:

$102^{\frac{2}{3} }$

2. If you want to write it as a decimal, you can convert the fraction as a decimal by dividing the numerator by the denominator and then, you must add this to the whole number part:

$102+\frac{2}{3}=102+0.67=102.67$