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4 years ago

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Fernando and Roger are both in an art class. Fernando has created 40 projects in class this year. Fernando has created five time

s as many projects as Roger. Create a multiplication equation that represents the situation. Then, solve how many projects Roger has created this year in art class?

1 answer:

Natali [406]4 years ago

3 0

40x5= 200 I'm not sure who created five times more projects than the other, but whoever did, created 200 projects.

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If sin (7y) = cos (5y + 14), find y.

Reil [10]

Answer:

Step-by-step explanation:

sin(7y)=cos(5y+14)=sin(90-(5y+14))=sin(76-5y)

7y=76-5y

12y=76

y=76/12=19/3

or

sin(7y)=cos (5y+14)=sin (90+(5y+14))=sin (5y+104)

7y=5y+104

2y=104

y=52

7 0

3 years ago

Solve x2 − 12x + 5 = 0 using the completing-the-square method. x = six plus or minus the square root of five x = negative six pl

Andru [333]

we are given

$x^2-12x+5=0$

we have to solve it by completing square method

step-1: Move 5 on right side

$x^2-12x+5-5=0-5$

$x^2-12x=-5$

step-2: Break middle term

$x^2-2*6*x=-5$

step-3: Add 6^2 both sides

$x^2-2*6*x+(6)^2=-5+(6)^2$

$(x-6)^2=31$

step-3: Solve for x

$\sqrt{(x-6)^2} =\sqrt{31}$

we wil get two values

First value is

$x-6=\sqrt{31}$

add both sides 6

$x-6+6=6+\sqrt{31}$

$x=6+\sqrt{31}$

Second value is

$x-6=-\sqrt{31}$

add both sides 6

$x-6+6=6-\sqrt{31}$

$x=6-\sqrt{31}$

so, solutions are

$x=6+\sqrt{31}$

$x=6-\sqrt{31}$ .............Answer

5 0

3 years ago

at a particular high school, 42% of the students participate in sports and 25% of the students participate in drama. if 53% of t

baherus [9]

The probability that a student participates in both sports and drama is $0.14$ .

<h3>What is the formula for P(AUB), where A and B are any two events?</h3>

If $A$ and $B$ are any two events, then the probability of the joint event $(A\cup B)$ is given by the following formula: $P(A\cup B)=P(A)+P(B)-P(A\cap B)$

Given that 42% of the students participate in sports and 25% of the students participate in drama and 53% of the students participate in either sports or drama.

Suppose $S$ denotes that "a student participates in sports" and $D$ denotes that "a student participates in drama".
So, we have $P(S)=\frac{42}{100}=0.42$ , $P(D)=\frac{25}{100}=0.25$ , $P(S\cup D)=\frac{53}{100}=0.53$ .

We want to find the probability that a student participates in both sports and drama i.e., we want to find $P(S\cap D)$ .

By the above formula, we obtain:

$P(S\cup D)=P(S)+P(D)-P(S\cap D)\\\Longrightarrow P(S\cap D)=P(S)+P(D)-P(S\cup D)\\\Longrightarrow P(S\cap D)=0.42+0.25-0.53\\\therefore P(S\cap D)=0.14=\frac{14}{100}$

Therefore, the probability that a student participates in both sports and drama is $0.14$ .

To learn more about probability, refer: brainly.com/question/24756209

#SPJ9

6 0

2 years ago

Read 2 more answers

What is the inequality of 10p – 8 ≥ 12.

LenaWriter [7]

Answer:

p > 2

Step-by-step explanation:

3 0

3 years ago

If 9x x 3x+1 = 2187, what is the value of x?<br><br><br><br><br>

Snezhnost [94]

Answer:

x = 80.96

Step-by-step explanation:

9x * 3x +1 = 2187

27x +1 = 2187

27x = 2187-1

27x = 2186

x = 2186/27 = 80.96(2dp)

7 0

3 years ago