At a rate of 78 ounce of water per hour, it would take 23,424 hours to drain the pond.
<h3>How long will it take to drain the pond?</h3>
First of all, we would use an appropriate conversion factor to convert the given units of water to the same unit. Thus, we would convert the unit of the pond's volume to ounce as follows:
Conversion factor:
1 gallon = 128 ounce.
14,274 gallons = X ounce
Cross-multiplying, we have:
X = 14,274 × 128
X = 1,827,072 ounces.
Now, we can calculate the time:
Rate = volume/time
Time = volume/rate
Time = 1,827,072/78
Time = 23,424 hours.
Read more on rate of change here: brainly.com/question/15648128
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Complete Question:
A pond at a hotel holds 14,274 gallons of water. The groundskeeper drains the pond at a rate of 78 ounce of water per hour. How long will it take to drain the pond?
Answer:
Step-by-step explanation:
cost of 6 potatoes=24.65-18.95=5.70 $
cost of 1 potato=5.70÷9=0.95 $
Answer: Let length = 2x + 3
Let width = x
Area = 54 ft2
length × width = Area
x(2x + 3) = 54
2x2 + 3x = 54
2x2 + 3x - 54 = 0
(2x - 9)(x + 6) = 0
x = 9/2 and x = -6
x = 4.5 and x = -6
We accept x = 4.5 because length cannot be a negative value. Substituting this value into the dimensions:
width = 4.5 ft
length = 2(4.5) + 3 = 9 + 3 = 12 ft
Step-by-step explanation:
If you put 0 in for y then x=2
4. (2,0)