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dybincka [34]
3 years ago
10

How do you simplify 4x + 2y +2x - 7y +8 - 5x -2

Mathematics
2 answers:
Svetradugi [14.3K]3 years ago
8 0

Answer: x-5y+6

Step-by-step explanation: combine like terms

4x+2x-5x=x

2y-7y=-5y

8-2=6

xz_007 [3.2K]3 years ago
7 0

Answer:

x-5y-10

Step-by-step explanation:

collect like terms

(4x+2x−5x)+(2y−7y)+(−8−2)

then simplify

x-5y-10

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Ava and Kelly ran a road race, starting from the same place at the same time. Ava ran at an average speed of 6 miles per hour. K
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<h2>Hello!</h2>

The answer is:

Ava and Kelly will be 3/4 mile apart after 0.375 hours.

<h2>Why?</h2>

To calculate when will Ava and Kelly be 3/4 mile apart, we need to write the equations for both Ava's and Kelly's positions.

Writing the equations we have:

For Ava:

x_A=x_o+v_ot\\\\x_A=0+v_o*t\\\\x_A=v_{o(ava)*t

For Kelly:

We need to calculate when Kelly will be 3/4 mile apart becase is running faster than Ava, so, writing the equation we have:

x_K=x_A+\frac{3}{4}mile=x_o+v_{o(Kelly)}*t

Now, substituting the equation for Ava into the equation for Kelly, we have:

x_A+\frac{3}{4}mile=x_o+v_{o(Kelly)}*t

v_{o(ava)*t+\frac{3}{4}mile}=x_o+v_{o(Kelly)}*t

v_{o(ava)*t+0.75mile}=x_{o}+v_{o(Kelly)}*t\\\\6mph*t+0.75mile=8mph*t\\\\0.75mile=2mph*t\\\\t=\frac{0.75miles}{2mph}=0.375hours

To prove  that the result is correct, we just need to substitute the obtained value for time into both equations, so, substutiting we have:

For Ava:

x_A=v_{o(ava)*t=6mph*0.375hours=2.25miles

For Kelly:

x_K=v_{o(Kelly)}*t=8mph*0.375=3miles

There is a difference of 0.75 miles or 3/4 mile between Ava and Kelly, so, the obtained value for time is correct.

Therefore, we have that Ava and Kelly will be 3/4 mile apart after 0.375 hours.

Have a nice day!

5 0
3 years ago
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