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dlinn [17]
3 years ago
7

I need help

Mathematics
2 answers:
victus00 [196]3 years ago
4 0

Answer:

About 5, 805 grams remaining.

Step-by-step explanation:

We are given that every 27 years, the mass of Element X decreases by half.

We can write an exponential function to model the situation. The standard exponential function is given by:

→ f(t)=a(r)^t

Where a is the initial amount, r is the rate, and t is the time, in this case years.

Since it is halved, our rate r is 1/2.

Since it is halved for every 27 years, for t, it will be t/27.

Therefore, our function is:

→ f(t)=a(1/2)^t/27

Our initial sample is 7,900 grams. Hence, a = 7900:

→ f(t)=7900(1/2)^t/27

We want to find the remaining amount after 12 years. So, t = 12. Use a calculator:

→ f(12)=7900(1/2)^12/27 ≈5805 grams

After 12 years, there will be about 5805 grams remaining.

s2008m [1.1K]3 years ago
3 0

Answer:

About 5, 805 grams remaining.

Step-by-step explanation:

We are given that every 27 years, the mass of Element X decreases by half.

We can write an exponential function to model the situation. The standard exponential function is given by:

\displaystyle f(t)=a(r)^t

Where <em>a</em> is the initial amount,<em> r</em> is the rate, and <em>t</em> is the time, in this case years.

Since it is halved, our rate <em>r </em>is 1/2.

Since it is halved for every 27 years, for <em>t</em>, it will be <em>t/27.</em>

Therefore, our function is:

\displaystyle f(t)=a\Big(\frac{1}{2}\Big)^{t/27}

Our initial sample is 7,900 grams. Hence, <em>a</em> = 7900:

\displaystyle f(t)=7900\Big(\frac{1}{2}\Big)^{t/27}

We want to find the remaining amount after 12 years. So, <em>t</em> = 12. Use a calculator:

\displaystyle f(12)=7900\Big(\frac{1}{2}\Big)^{12/27}\approx5805\text{ grams}

After 12 years, there will be about 5805 grams remaining.

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