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3 years ago

PLZ I WILL GIVE BRAILIEST TO THE FIRST ANSWER

2 answers:

8 0

Option B is the correct answer.

3 is greater than -5, -9, and -1.

Hint: Remember to distribute the negative when solving. A negative directly outside outside of and to the left the parenthesis times a negative number inside the parenthesis makes that number positive.

So for option B, you can simplify it to -3 +4 +2. And that equals 3.

A) -3+-4-(-2) = -5

B) -3-(-4)-(-2) = 3

C) -3+(-4)-2 = -9

D) -3-(-4)-2 = -1

Liula [17]3 years ago

6 0

A) -3+-4-(-2) = -5

B) -3-(-4)-(-2) = 3

C) -3+(-4)-2 = -9

D) -3-(-4)-2 = -1

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HELP ME PLEASE! A representation of a linear equation in two variables is graphed below.

Kamila [148]

Option C, y = 1/2 x -2 is the correct answer

4 0

3 years ago

PLEASE HELPPPPPPP

uysha [10]

Answer:

the answer would be 1,-8

6 0

2 years ago

A ball of radius 15 has a round hole of radius 5 drilled through its center. Find the volume of the resulting solid. Hint: The u

OverLord2011 [107]

Answer:

The volume of the ball with the drilled hole is:

$\displaystyle\frac{8000\pi\sqrt{2}}{3}$

Step-by-step explanation:

See attached a sketch of the region that is revolved about the y-axis to produce the upper half of the ball. Notice the function y is the equation of a circle centered at the origin with radius 15:

$x^2+y^2=15^2\to y=\sqrt{225-x^2}$

Then we set the integral for the volume by using shell method:

$\displaystyle\int_5^{15}2\pi x\sqrt{225-x^2}dx$

That can be solved by substitution:

$u=225-x^2\to du=-2xdx$

The limits of integration also change:

For x=5: $u=225-5^2=200$

For x=15: $u=225-15^2=0$

So the integral becomes:

$\displaystyle -\int_{200}^{0}\pi \sqrt{u}du$

If we flip the limits we also get rid of the minus in front, and writing the root as an exponent we get:

$\displaystyle \int_{0}^{200}\pi u^{1/2}du$

Then applying the basic rule we get:

$\displaystyle\frac{2\pi}{3}u^{3/2}\Bigg|_0^{200}=\frac{2\pi(200\sqrt{200})}{3}=\frac{400\pi(10)\sqrt{2}}{3}=\frac{4000\pi\sqrt{2}}{3}$

Since that is just half of the solid, we multiply by 2 to get the complete volume:

$\displaystyle\frac{2\cdot4000\pi\sqrt{2}}{3}$

$=\displaystyle\frac{8000\pi\sqrt{2}}{3}$

5 0

3 years ago

Find K such that the points (-2, 5), (2, 8) and (6, K) are collinear.

damaskus [11]

Answer:

k = 11

Step-by-step explanation:

let the points be A(-2,5), B(2,8), C(6,K).

for the points to be collinear slope of line AB maust be equal to line BC.

slope of line AB = $\frac{8-5}{2+2}=\frac{3}{4}$

slope of line BC = $\frac{k-8}{6-2}=\frac{k-8}{4}$

therefore $\frac{k-8}{4}= \frac{3}{4}$

therefore k = 8 + 3

k = 11

8 0

3 years ago

For questions 6-9, match the equation to its corresponding graph.

Julli [10]

6.b
7.d
8.a
9.c
see attached image. sorry that’s it’s all jumbled up weird, i could only figure out how to put them all together using photoshop. hope these help you out :))

8 0

3 years ago