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WARRIOR [948]
3 years ago
11

Find a2 and a3 for the geometric sequence 4, a2, a3, 108.

Mathematics
1 answer:
LekaFEV [45]3 years ago
3 0

9514 1404 393

Answer:

  a2 = 12

  a3 = 36

Step-by-step explanation:

Terms of a geometric sequence have a common ratio. If we call that ratio r, then we have ...

  a2 = 4r

  a3 = (a2)r = 4r^2

  108 = (a3)r = 4r^3

  27 = r^3 . . . . . . . . . . . divide by 4

  3 = r . . . . . . . . . . cube root

__

  a2 = 4(3) = 12

  a3 = 12(3) = 36

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