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Tresset [83]
3 years ago
14

What is the product of the coordinates of the midpoint of a line segment with endpoints at (1,1) and (-7,5)?

Mathematics
1 answer:
puteri [66]3 years ago
3 0

9514 1404 393

Answer:

  (-3, 3)

Step-by-step explanation:

The midpoint of a line segment is the average of the end point coordinates:

  ((1, 1) +(-7, 5))/2 = (1 -7, 1 +5)/2 = (-6, 6)/2 = (-3, 3) . . . midpoint coordinates

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Step-by-step explanation:

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vector AB(3-(-6); 5-7)

vector AB(9;-2)

AB= \sqrt{9^{2}+(-2)^{2}  } = \sqrt{85}

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M is the midpoint of AB

we have B(-5;10) and M(1;7)

let A(x;y)

(x-5)/2 = 1 ⇒ x-5 = 2⇒ x = 7

(10=y)/2 = 7⇒ 10+y = 14 ⇒y= 4

so : A(7;4)

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the center of the circle is the midponit of the line joining both ends of the diameter

let A(x;y) be the other end

(-2+x)/2 = 2 ⇒ -2+x = 4⇒ x= 6

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so the coordinates of the other end are (6; -7)

  • 4

A,B and C are collinear such as AB=BC so b is the midpoint of AC

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((-3=x)/2 = 7 ⇒ -3+x = 14 ⇒ x = 17

so x= 17 and y = -2

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You factor out primes from the root, for example:
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Answer:

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Step-by-step explanation:

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3 years ago
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Answer:

(6,3)

Step-by-step explanation:

y=2/3 x - 1

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