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2 years ago

What is the product of the coordinates of the midpoint of a line segment with endpoints at (1,1) and (-7,5)?

Mathematics

1 answer:

puteri [66]2 years ago

3 0

9514 1404 393

Answer:

(-3, 3)

Step-by-step explanation:

The midpoint of a line segment is the average of the end point coordinates:

((1, 1) +(-7, 5))/2 = (1 -7, 1 +5)/2 = (-6, 6)/2 = (-3, 3) . . . midpoint coordinates

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According to an almanac, 60% of adult smokers started smoking before turning 18 years old. (a) compute the mean and standard

larisa [96]

The given problem describes a binomial distribution with p = 60% = 0.6. Given that there are 400 trials, i.e. n = 400.

a.) The mean is given by:

$\mu=np=400\times0.6=240$

The standard deviation is given by:

$\sigma=\sqrt{npq} \\ \\ =\sqrt{np(1-p)} \\ \\ =\sqrt{400(0.6)(0.4)} \\ \\ =\sqrt{96}=9.80$

b.) The mean means that in an experiment of 400 adult smokers, we expect on the average to get about 240 smokers who started smoking before turning 18 years.

c.) It would be unusual to observe <span>340 smokers who started smoking before turning 18 years old in a random sample of 400 adult smokers because 340 is far greater than the mean of the distribution.
340 is greater than 3 standard deviations from the mean of the distribution.</span>

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2 years ago

The diameter of a circle is 14 in. Find its area in terms of

Luda [366]

Answer:

Given - Diameter of circle = 14 in

To find - Area of circle

Solution -

Diameter= 2 × Radius

14 = 2 × R

14/2 = R

7 = R

Area of circle= π r^²

22/7 × 7 × 7

22 × 7

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2 years ago

Day, everything at a store is on sale. The store offers a 20% discount.

Nutka1998 [239]

Answer:

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Step-by-step explanation:

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2 years ago

Which of the following equations represents the perpendicular bisector of WX graphed below?

kotykmax [81]

The coordinates of the 2 given points are W(-5, 2), and X(5, -4).

First, we find the midpoint M using the midpoint formula:

$\displaystyle{ M_{WX}= (\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2} )= (\frac{-5+5}{2}, \frac{2+(-4)}{2} )=(0, -1).$

Nex, we find the slope of the line containing M, perpendicular to WX. We know that if m and n are the slopes of 2 parallel lines, then mn=-1.

The slope of WX is $\displaystyle{ m= \frac{y_2-y_1}{x_2-x_1}= \frac{2-(-4)}{-5-5}= \frac{6}{-10}= -\frac{3}{5}$ .

Thus, the slope n of the perpendicular line is $\displaystyle{ \frac{5}{3}$ .

The equation of the line with slope $\displaystyle{ n= \frac{5}{3}$ containing the point M(0, -1) is given by:

$\displaystyle{ y-(-1)=\frac{5}{3}(x-0)$

$\displaystyle{ y+1= \frac{5}{3}x$

$\displaystyle{ 3y+3=5x$

$\displaystyle{ 5x-3y-3=0$

Answer: 5x-3y-3=0

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