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Tresset [83]
3 years ago
14

What is the product of the coordinates of the midpoint of a line segment with endpoints at (1,1) and (-7,5)?

Mathematics
1 answer:
puteri [66]3 years ago
3 0

9514 1404 393

Answer:

  (-3, 3)

Step-by-step explanation:

The midpoint of a line segment is the average of the end point coordinates:

  ((1, 1) +(-7, 5))/2 = (1 -7, 1 +5)/2 = (-6, 6)/2 = (-3, 3) . . . midpoint coordinates

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pls help, i need to write an essay explaining what the difference is between finding the volume and total surface of a shape
Vinil7 [7]

Answer:

The surface area applies to how much space a SOLID objects occupies while volume is  the space that a substance (solid, liquid, gas, or plasma) or shape occupies or contains, so volume can be anything.

Step-by-step explanation:

you can't really write an essay-

8 0
3 years ago
Read 2 more answers
Consider these scenarios. 1. A piano weighs 5.5 × 102 units.   2. A grain of salt weighs 1.02 × 10-3 units.   3. A tractor trail
zhannawk [14.2K]

Answer:

1) pounds

2) grams

3) tons

Step-by-step explanation:

The suitable measurements for the scenarios are:

1) A piano weighs 5.5 × 10² units

  550 Ib (pounds)

2) A grain of salt weighs 1.02 × 10^-3  units

    0.00102 grams

3) A tractor trailer weighs 8.8 × 10^1 units

    88 ton

   

10²g = 1kg

10^-3g = miligrams

10^1 g = decagram

5 0
3 years ago
Read 2 more answers
How do you solve his with working
AlexFokin [52]
Check the picture below.

a)

so the perimeter will include "part" of the circumference of the green circle, and it will include "part" of the red encircled section, plus the endpoints where the pathway ends.

the endpoints, are just 2 meters long, as you can see 2+15+2 is 19, or the radius of the "outer radius".

let's find the circumference of the green circle, and then subtract the arc of that sector that's not part of the perimeter.

and then let's get the circumference of the red encircled section, and also subtract the arc of that sector, and then we add the endpoints and that's the perimeter.

\bf \begin{array}{cllll}
\textit{circumference of a circle}\\\\ 
2\pi r
\end{array}\qquad \qquad \qquad \qquad 
\begin{array}{cllll}
\textit{arc's length}\\\\
s=\cfrac{\theta r\pi }{180}
\end{array}\\\\
-------------------------------

\bf \stackrel{\stackrel{green~circle}{perimeter}}{2\pi(7.5) }~-~\stackrel{\stackrel{green~circle}{arc}}{\cfrac{(135)(7.5)\pi }{180}}~+
\stackrel{\stackrel{red~section}{perimeter}}{2\pi(9.5) }~-~\stackrel{\stackrel{red~section}{arc}}{\cfrac{(135)(9.5)\pi }{180}}+\stackrel{endpoints}{2+2}
\\\\\\
15\pi -\cfrac{45\pi }{8}+19\pi -\cfrac{57\pi }{8}+4\implies \cfrac{85\pi }{4}+4\quad \approx \quad 70.7588438888



b)

we do about the same here as well, we get the full area of the red encircled area, and then subtract the sector with 135°, and then subtract the sector of the green circle that is 360° - 135°, or 225°, the part that wasn't included in the previous subtraction.


\bf \begin{array}{cllll}
\textit{area of a circle}\\\\ 
\pi r^2
\end{array}\qquad \qquad \qquad \qquad 
\begin{array}{cllll}
\textit{area of a sector of a circle}\\\\
s=\cfrac{\theta r^2\pi }{360}
\end{array}\\\\
-------------------------------

\bf \stackrel{\stackrel{red~section}{area}}{\pi(9.5^2) }~-~\stackrel{\stackrel{red~section}{sector}}{\cfrac{(135)(9.5^2)\pi }{360}}-\stackrel{\stackrel{green~circle}{sector}}{\cfrac{(225)(7.5^2)\pi }{360}}
\\\\\\
90.25\pi -\cfrac{1083\pi }{32}-\cfrac{1125\pi }{32}\implies \cfrac{85\pi }{4}\quad \approx\quad 66.75884

7 0
3 years ago
Kathleen deposits $20 into her account that earns 2.5% interest that is compounded twice a year. How much money will Kathleen ha
Arada [10]
A=20×(1+0.025÷2)^(2×30)
A=42.14
8 0
3 years ago
The temperature Rose 4 degrees each hour for 3 hours what was the total change in the temperature?
ozzi

12 degrees change in temp.


4 0
3 years ago
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