Answer:
Problem B: x = 12; m<EFG = 48
Problem C: m<G = 60; m<J = 120
Step-by-step explanation:
Problem B.
Angles EFG and IFH are vertical angles, so they are congruent.
m<EFG = m<IFH
4x = 48
x = 12
m<EFG = m<IFH = 48
Problem C.
One angle is marked a right angle, so its measure is 90 deg.
The next angle counterclockwise is marked 30 deg.
Add these two measures together, and you get 120 deg.
<J is vertical with the angle whose measure is 120 deg, so m<J = 120 deg.
Angles G and J from a linear pair, so they are supplementary, and the sum of their measures is 180 deg.
m<G = 180 - 120 = 60
Answer:
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Step-by-step explanation:
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Yes these r similar!
Hope this helps!
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I believe this just uses the Pythagorean Theorem. A^2+B^2=C^2. So:
15^2+B^2=25^2. Simplified this is,
225+B^2=625
625-225=400
B^2=400
√ B=<span>√ 400
</span>B=20
