7 x 21 is equivalent to 21 x 7
also 3 x 49
We know that, as per a corollary of intermediate value theorem, if a function f(x) is continuous on a closed interval [a,b], and values of f(a) and f(b) have opposite signs, then the function f(x) is guaranteed to have a zero on the interval (a,b).
So, basically, we need to figure out two values of x, at which the values of the given cubic function have opposite signs.
Let us consider the interval [-2,1].
We have . Upon substituting the values x=-2 and x=1 one by one, we get:
We can see that signs of values of the function at x=-2 and x=1 are opposite, therefore, as per intermediate value theorem, the function is guaranteed to have a zero on the interval [-2,1]
Your answer would be 2x^2y(x^2y^2-6xy-4)
Answer:
The answer is A.
Step-by-step explanation:
1/3 - 1/4 = (4-3)/12 = 1/12
1/4 - 1/6 = (6-4)/24 = 2/24 = 1/12
1/12
Answer:
You can simulate any probability between 0-1 with a coin if you do enough flips to assign the possibility of the combinations appearing as an event, always taking into consideration that if you want to represent an event of , y would have to be something or you will need to take one of the set of flips as "try again", where 2 represents the number of equal possibilities in a fair coin (head and tails, so 2 possibilities) and n is the number of flips.
Let's take the numbers given in the problem as examples, you want to represent 1/3 and 2/3. So the number that comes closer to the denominator is =4 or two flips.
This gives of the events:
HH
HT
TH
TT
Each with 1/4 chance of appearing, but we ant 1/3 and 2/3. We can simulate it by making:
HH - 1/3
HT - 1/3
TH - 1/3
TT - "Try again"
We can then make any two combinations of the first three the 2/3, and the other one 1/3. For example, HH would be 1/3 and either HT or TH 2/3. If TT appears after 2 flips, you will just need to flip two times again.