Which system of linear inequalities is represented by

Please find the surface area.

nevsk [136]

Answer:

multiply the givens. use a calculator

7 0

3 years ago

Which Theroms can be used to determine that the triangles are congruent <br>

Ivanshal [37]

Answer:

SAS

Step-by-step explanation:

side GF is shared.

angles between the sides, ∠EGF ≅ ∠HFG because they are corresponding congruent angles

6 0

2 years ago

How many tiles of 10cm by a 6cm will be needed to pave a rectangular path of 5m by 3m

kherson [118]

Answer:

2500 tiles

Step-by-step explanation:

convert the path to the same units, one m = 100 cm

path= 500 cm x 300 cm

path area = 150,000 cm^2

each tile = 10x6 = 60 cm^2

150,000/60 = 2500 tiles

6 0

2 years ago

Which of the following can be determined from a box-and-whisker plot?

elixir [45]

<h3>Answer: B) Median</h3>

The middle vertical line inside the box is the median or the value of Q2. The term "median" is used more often instead of Q2, but your book may use this terminology as well.

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side notes:

* The left and right edges of the box are Q1 and Q3 respectively

* The IQR (interquartile range) is found by subtracting Q3 and Q1

* The min and max are the left and right most edges of the the whiskers, this is assuming there are no outliers

* There is no way to get the mean or mode from a box and whisker plot alone.

* The term "average" is too vague and could refer to mean, median, or mode.

8 0

3 years ago

The National Center for Education Statistics reported that 47% of college students work to pay for tuition and living expenses.

Luden [163]

Using the z-distribution, it is found that the 95% confidence interval for the proportion of college students who work to pay for tuition and living expenses is: (0.4239, 0.5161).

If we had increased the confidence level, the margin of error also would have increased.

<h3>What is a confidence interval of proportions?</h3>

A confidence interval of proportions is given by:

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which:

$\pi$ is the sample proportion.

z is the critical value.

n is the sample size.

In this problem, we have a 95% confidence level, hence $\alpha = 0.95$ , z is the value of Z that has a p-value of $\frac{1+0.95}{2} = 0.975$ , so the critical value is z = 1.96. Increasing the confidence level, z also increases, hence the margin of error also would have increased.

The sample size and the estimate are given as follows:

$n = 450, \pi = 0.47$ .

The lower and the upper bound of the interval are given, respectively, by:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.47 - 1.96\sqrt{\frac{0.47(0.53)}{450}} = 0.4239$

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.47 + 1.96\sqrt{\frac{0.47(0.53)}{450}} = 0.5161$

The 95% confidence interval for the proportion of college students who work to pay for tuition and living expenses is: (0.4239, 0.5161).

More can be learned about the z-distribution at brainly.com/question/25890103

#SPJ1

5 0

1 year ago