Answer:
Step-by-step explanation:
Let's say that the time it took him to get to work in the morning is t hours. Then the time it took him to get home in the afternoon must be 1 - t hours. We know that for any trip, distance equals rate times time or d = rt . That means that the distance he drove to work is given by , but we also know that the distance he drove to get home must be the same distance, because he took the same route (and, presumably, no one picked up him house and moved it while he was at work) so for the trip home we can say d = 30 × (1 - t) and since the distances are equal, we can say:
45t = 30 × (1 - t)
45t = 30 - 30t
45t + 30t = 30
75t = 30
t = 30/75
t = 2 /5 hour to drive to work at 45mph
Since , d = rt
d = 45 ×(2/5) = 18miles
The largest perfect square factor of 18 is 9.
Answer:

Step-by-step explanation:
Given

Required
Find the equivalent
We start by changing the / to *


Factorize 10a - 5

Expand 4a² - 1


Express (2a)² - 1² as a difference of two squares
Difference of two squares is such that: 
The expression becomes

Combine both fractions to form a single fraction

Divide the numerator and denominator by 2a - 1

Simplify the numerator


Hence,
= 
Answer:
162, sorry if this is wrong
Step-by-step explanation:
9 feet on the sides hope this helps