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KIM [24]
3 years ago
14

Use technology or a z-score table to answer the question.

Mathematics
1 answer:
matrenka [14]3 years ago
4 0

Answer:

D

Step-by-step explanation:

I usually use a z-score table, but you can do this with a calculator.

If we go to a z-score table, we first look up the first two digits (in this case, 2.8) in the far left column.  Then we find the hundredths digit in the top row (0.07).  Where they intersect is P(z < 2.87).

P(z < 2.87) = 0.9979

Answer D.

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Use the distributive property to find the missing number.<br> __× (9 + 8) = (15 × 9) + (15 × 8)
BARSIC [14]

Answer:

The missing number is 15

5 0
3 years ago
!NUMBER 4! please help!! show all work please
snow_lady [41]

Answer:

C. 88

Explanation:

f(x) = 4x + 8  ||  g(x) = x² + x

fg( -5 )

go from right to left in such function problems.

replace x with [ -5 ]

f( (-5)²  -5)

f(20)

[ replace x with 20 ]

4(20) + 8

80 + 8

88

7 0
2 years ago
businessText message users receive or send an average of 62.7 text messages per day. How many text messages does a text message
KiRa [710]

Answer:

(a) The probability that a text message user receives or sends three messages per hour is 0.2180.

(b) The probability that a text message user receives or sends more than three messages per hour is 0.2667.

Step-by-step explanation:

Let <em>X</em> = number of text messages receive or send in an hour.

The random variable <em>X</em> follows a Poisson distribution with parameter <em>λ</em>.

It is provided that users receive or send 62.7 text messages in 24 hours.

Then the average number of text messages received or sent in an hour is: \lambda=\frac{62.7}{24}= 2.6125.

The probability of a random variable can be computed using the formula:

P(X=x)=\frac{e^{-\lambda}\lambda^{x}}{x!} ;\ x=0, 1, 2, 3, ...

(a)

Compute the probability that a text message user receives or sends three messages per hour as follows:

P(X=3)=\frac{e^{-2.6125}(2.6125)^{3}}{3!} =0.21798\approx0.2180

Thus, the probability that a text message user receives or sends three messages per hour is 0.2180.

(b)

Compute the probability that a text message user receives or sends more than three messages per hour as follows:

P (X > 3) = 1 - P (X ≤ 3)

              = 1 - P (X = 0) - P (X = 1) - P (X = 2) - P (X = 3)

             =1-\frac{e^{-2.6125}(2.6125)^{0}}{0!}-\frac{e^{-2.6125}(2.6125)^{1}}{1!}-\frac{e^{-2.6125}(2.6125)^{2}}{2!}-\frac{e^{-2.6125}(2.6125)^{3}}{3!}\\=1-0.0734-0.1916-0.2503-0.2180\\=0.2667

Thus, the probability that a text message user receives or sends more than three messages per hour is 0.2667.

6 0
3 years ago
If Eugene can buy three cantaloupes for $7. Then how many can you buy with $14
suter [353]
I believe the answer would be 6 because 7x2=14 so 3 cantaloupes x 2= 6
8 0
3 years ago
O is the centre of the circle, EF is a tangent, angle BCE=28 degrees, angle ACD=31 degrees.
Yuki888 [10]

Answer:

a. 28˚

b. 76˚

c. 104˚

d. 56˚

Step-by-step explanation

a. because angle between tangent and chord is equal to the angle(s) in alternate segment.

b. because angles in triangles add up to 180˚, 180-28=152 and because isosceles triangle, 152/2=76˚

c. because angles in triangles add up to 180˚ and opposite angles in a cyclic quadrilateral add up to 180˚, 31+76=107, 180-107=73, 73-28=45, angles in triangle so 180-(31+45)=104˚

d. 28*2=56˚ because angles at circumference are half angles at centre

4 0
3 years ago
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