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Svetllana [295]
3 years ago
7

30 POINTS! HELP!!

Mathematics
1 answer:
lakkis [162]3 years ago
7 0
Answer is 1.08, i believe this might be an estimated number, with the way I did it
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What would the answer be for this equation? 3a^3b^2x2a^2b^5
Wewaii [24]

9514 1404 393

Answer:

6a^5b^7

Step-by-step explanation:

The applicable rule of exponents is ...

  (a^b)(a^c) = a^(b+c)

__

It looks like you want to simplify ...

  3a^3b^2\times 2a^2b^5=(3\cdot2)a^{3+2}b^{2+5}=\boxed{6a^5b^7}

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3 years ago
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you want to mail a gift that is in the shape of a rectangular prism with the dimensions 25 cm by 32 CM by 40 cm .what is the min
Mkey [24]
Check the picture below.

notice, the gift box is just 6 rectangles stacked up to each other at the edges,

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top and bottom, two rectangles of 25x32

front and back, two rectangles of 25x40

so, just get the area of all 6 rectangles, add them up, and that's the "surface area" of the rectangular prism, and that's how much paper will be needed to cover it.

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4 years ago
14) A blizzard produced 9 - inches of snow. The
Arisa [49]

Answer:

2 3/8 in.

Step-by-step explanation:

9\frac{1}{2}-7\frac{1}{8}\\\\9\frac{4}{8}-7\frac{1}{8}\\\\2\frac{3}{8}

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3 years ago
Which sum or difference identity would you use to verify that cos (180° - q) = -cos q?
Phantasy [73]

Answer:

\cos (a-b)=\cos a \cos b+\sin a \sin b

Step-by-step explanation:

 Given : \cos (180^{\circ}-q)=-\cos q

We have to write which identity we will use to prove the given statement.

Consider \cos (180^{\circ}-q)=-\cos q

Take left hand side of given expression \cos (180^{\circ}-q)

We know

\cos (a-b)=\cos a \cos b+\sin a \sin b

Comparing , we get, a= 180° and b = q

Substitute , we get,

\cos (180^{\circ}-q)=\cos 180^{\circ}  \cos (q)+\sin q \sin 180^{\circ}

Also, we know \sin 180^{\circ}=0 and \cos 180^{\circ}=-1

Substitute, we get,

\cos (180^{\circ}-q)=-1\cdot \cos (q)+\sin q \cdot 0

Simplify , we get,

\cos (180^{\circ}-q)=-\cos (q)

Hence, use difference identity to  prove the given result.

7 0
3 years ago
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Answer:

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caca con caca e caca en bolas

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