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2 years ago

Solve 1/f=1/a+1/b for f

Mathematics

1 answer:

Alika [10]2 years ago

3 0

Answer:

f=ab/a+b

Step-by-step explanation:

Let's solve for f.

1/f=1/a+1/b

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Write the value f (1) =1 in an order pair

kenny6666 [7]

Answer:

(1, 1)

Step-by-step explanation:

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2 years ago

The lengths of the sides of a triangle are consecutive odd integers. If the perimeter is 1 less than 4 times the shortest side,

Lubov Fominskaja [6]

Let the shortest side be x. Then the other two sides will be x+1 and x+2.

Perimeter = P = sum of the lengths of all three sides = x + (x+1) + (x+2)

This perimeter = 4x -1 (1 less than 4 times the shortest side).

Then x + x + 1 + x + 2 = 4x - 1
or: 3x + 3 = 4x -1 Subtr. 3x from both sides:
3 = x - 1

x=4, x+1=5, and x+2=6

The 3 sides have lengths 4, 5 and 6.

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2 years ago

Find the hypotenuse of an isosceles right triangle when the legs each measure 3\sqrt{x} 2inches.

Tresset [83]

The hypotenuse of the right triangle measures 3 units.

<h3>How to find the hypotenuse?</h3>

Here we know that both legs measure:

$L =\frac{3}{\sqrt{2} }$

If we use the Pythagorean theorem, we will see that the hypotenuse H can be written as:

$H^2 = (\frac{3}{\sqrt{2} } )^2 + (\frac{3}{\sqrt{2} } )^2 \\\\H^2 = \frac{9}{2} + \frac{9}{2} = \frac{18}{2} = 9\\\\H = \sqrt{9} = 3$

Then we conclude that the hypotenuse of the right triangle measures 9 units.

If you want to learn more about right triangles:

brainly.com/question/2217700

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1 year ago

A computer processor costs $96.00. It is expected that in 8 months the processor will cost 3/4 its current price. How much will

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967.50

Step-by-step explanation:

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2 years ago

Read 2 more answers

X^3+7x^2+13x+4=0 Show all work

Softa [21]

$\displaystyle\\
x^3+7x^2+13x+4=0\\\\
x^3+\underbrace{4x^2+3x^2}_{7x^2}+\underbrace{12x+x}_{13x}+4=0\\\\
(x^3+4x^2) + (3x^2 + 12x)+(x+4)=0\\\\
x^2(x+4)+3x(x+4)+(x+4)=0\\\\
(x+4)(x^2 + 3x +1)=0\\\\
x+4 = 0~~~\Longrightarrow~~~\boxed{x_1 = -4}\\\\
x^2 + 3x +1=0\\\\
x_{23}= \frac{-b\pm \sqrt{b^2-4ac} }{2a}= \frac{-3\pm \sqrt{3^2-4\cdot 1 \cdot 1} }{2\cdot 1}= \frac{-3\pm \sqrt{5} }{2}\\\\
\boxed{x_2 = \frac{-3-\sqrt{5} }{2}}\\\\
\boxed{x_3 = \frac{-3+\sqrt{5} }{2}}$

4 0

2 years ago