241,864,704 many different passwords are possible.
The total characters of the password is six in which it is given that first character should start with W, X, Y or Z. So the first character can be filled in 4 ways.
For next five characters it can be any letter of the alphabet or any numeric digit so it will be 26 + 10 = 36.
So second, third, fourth, fifth and sixth space can be taken by 36 characters.
Therefore the total no. of passwords will be 4 * 36 * 36 * 36 * 36 * 36 that is equal to 241,864,704.
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Answer:
radius = 13
Step-by-step explanation:
Look at the attached picture below. We can calculate radius with the help of the Pythagorean theorem. But first we have to find out the values of the two legs.
First let's find the shorter leg.
<u>Equidistant Chords Theorem</u>
Two chords are congruent if they are equidistant from the center.
Chords in the picture are congruent and that means that the distance from the center to each of them is the same!
Let's calculate the distance. But to get the distance we have to find x first.
Since the distances are the same:
Therefore:
Let's focus on the longer leg. Since part of the radius is perpendicular to the chord, it actually bisects the chord! That means that the long leg is going to be a half of the length of the chord.
Therefore:
All that is left is the Pythagorean Theorem in the right triangle.
<u>Pythagorean Theorem</u>
Hypotenuse in our case is the radius.
Since 2 is less than or equal to 2, you input it into the first equation!
3•(2) -5
6-5
1
The answer is 1!
Answer: 5,940,000
Step-by-step explanation: So the number in the thousand place is the 3 beside the 9 in the thousand place. So when u you round that number, or will become a 4. So every thing behind the new 4, will become a 0. So the answer will become 5,940,000.
Answer:
9.0×10^3K/moles
Step-by-step explanation:
ionization energy of these electrons = Energy of photons - kinetic energy of the electrons
Given
Kinetic energy of electron = 1.34×10^5
Energy of photons = 1.43 x 105 kJ/mole
Required
Ionization energy of these electrons
Ionization energy of these electrons = 1.43×10^5-1.34×10^5
ionization energy of these electrons = 0.09×10^5 kJ/mol
= 9.0 × 10^3 kJ/mol
Hence the ionization energy of these electrons is 9.0×10^3K/moles
