What is b for the equation y=1/3x+b??

Plz help I don't get this it is so confusing

CaHeK987 [17]

It is not linear, as the 1st hour charged $25, and the 2nd hour charged $40, while the third hour charged $60, that's a $15 difference then a $20

6 0

3 years ago

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In the Venn diagram, consider U = {whole numbers 1-100}

Dmitry [639]

The question is what numbers satisfy A ∩ C.

The symbol ∩ means intersection, .i.e. you need to find the numbers that belong to both sets A and C. Those numbers might belong to the set C or not, because that is not a restriction.

Then lets find the numbers that belong to both sets, A and C.

Set A: perfect squares from A to 100:

1^2 = 1
2^2 = 4
3^2 = 9
4^2 = 16
5^2 = 25
6^2 = 36
7^2 = 49
8^2 = 64
9^2 = 81
10^2 = 100

=> A = {1, 4, 9, 16, 25, 36, 49, 64, 81, 100}

Set C: perfect fourths

1^4 = 1
2^4 = 16
3^4 = 81

C = {1, 16, 81?

As you see, all the perfect fourths are perfect squares, so the intersection of A and C is completed included in A. this is:

A ∩ C = C or A ∩ C = 1, 16, 81

On the other hand, the perfect cubes are:

1^3 = 1
2^3 = 8
3^3 = 27
4^3 = 81

B = {1, 8, 27, 81}

That means that the numbers 1 and 81 belong to the three sets, A, B, and C.

In the drawing you must place the number 16 inside the region that represents the intersection of A and C only, and the numbers 1 and 81 inside the intersection of the three sets A, B and C.

6 0

3 years ago

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Solve 3-²<br>I need work shown

skelet666 [1.2K]

$\huge\text{Hey there!}$

$\large\text{Equation: }\bold{3^{-2}}$

$\large\text{Lets convert }\bold{3^{-2}}\large\text{ into }\bold{3^2}\large\text{ temporarily...}$

$\large\text{Equation:} \bold{\dfrac{1}{3^2}}\\\\\bold{= \dfrac{1}{3\times3}}\\\\\bold{3\times3\rightarrow9\leftarrow\ solving\ for\ your\ DENOMINATOR\ (bottom\ number)}\\\\\bold{= \dfrac{1}{9}}\\\\\boxed{\boxed{\large\text{Answer: }\bold{\dfrac{1}{9}}}}\huge\checkmark$

$\textsf{Good luck on your assignment and enjoy your day!}$

~ $\frak{Amphitrite1040:)}$

3 0

3 years ago

Find the area of the composite figure

ehidna [41]

The figure is a trapezoid, albeit not possessing the same lengths for the left and right sides. If I'm not mistaken, it has another name or term. But I forgot.

Anyway, to solve the problem, let us chop-chop or break the figure into two parts or two polygons that we are familiar with - a rectangle and a triangle. See the attached image for a clearer presentation.

After breaking the original polygon into two parts as portrayed by the red broken line, we are also going to divide the equivalent value of each side.

Remember, a rectangle has two pairs of common sides. Since the upper side of the polygon has a length of 10 cm, then, the length of the lower side (the side at the left side of the broken line) is 10, too. The same goes for the length of the left side which is 5 cm, and therefore the length of the broken line is 5 cm. Please refer to the attached image, particularly the figures in green.

From the standpoint of the triangle, based on thee figure, it has a height of 5 cm and a base of 5 cm (15 cm- 10 cm). Did you get it? If yes, let's continue.

Solving Time! :D

1. Solve for the area of the rectangle.

$\begin{gathered}A_{rectangle}=L\times W\\=5\ cm \times 10\ cm\\=\bold{50\ cm^2}\end{gathered}$