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melomori [17]
2 years ago
15

Which numbers for b would make √b irrational​mark as brilliant!

Mathematics
1 answer:
just olya [345]2 years ago
8 0

Answer:

All of the options when substituted for b will make the root of b irrational

Step-by-step explanation:

Mathematically, surds are roots of non-perfect squares and they are tagged as irrational numbers

For b to be irrational, all of the numbers given would fit. This is because all of these numbers are non-perfect squares meaning they do not have square root.

So what this mean is that these numbers when put under the root umbrella are irrational numbers as they are not perfect squares

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3 years ago
Please help me urgently
lozanna [386]

Answer:

3/8 seems to be the most relevant answer

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2 years ago
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Find the smallest positive integer solution to the following system of congruences: x = 0 (mod 5) x = 8 (mod 11) The solution is
igomit [66]

Answer:

The smallest positive integer solution to the given system of congruences is 30.

Step-by-step explanation:

The given system of congruences is

x=0(mod5)

x=8(mod11)

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It means, if the number divided by 5, then remainder is 0 and if the same number is divided by 11, then the remainder is 8. It can be defined as

x=5m

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Now, we can say that m>n because m and n are positive integers.

For n=1,

5m=11(1)+8=19

5m=19

19 is not divisible by 5 so m is not an integer for n=1.

For n=2,

5m=11(2)+8

5m=30

m=6

The value of m is 6 and the value of n is 2. So the smallest positive integer solution to the given system of congruences is

x=5(6)=30

Therefore the smallest positive integer solution to the given system of congruences is 30.

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3 years ago
Watch help video<br> Find the exact length of the third side.<br> 50<br> 10
scZoUnD [109]

Answer:

40

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2 years ago
Evaluate the expression,<br> if x = 9, y = 3, and z = 5.<br> z2 • (x-y)
Bad White [126]

\huge\text{Hey there!}


\mathsf{z^2 \times (x - y)}

\mathsf{= 5^2 \times (9 - 3)}

\mathsf{= 5 \times 5 \times (9 - 3)}

\mathsf{= \bold{25}\times(9 - 3)}

\mathsf{= 25\times \bf 6}

\mathsf{= \bf 150}


\huge\text{Therefore, your answer should be: }

\huge\boxed{\frak{150}}\huge\checkmark


\huge\text{Good luck on your assignment \& enjoy your day!}


~\frak{Amphitrite1040:)}

3 0
1 year ago
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