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Papessa [141]
2 years ago
7

Fining the Unit Rate.​

Mathematics
1 answer:
MAVERICK [17]2 years ago
5 0

Answer:

See below ~

Step-by-step explanation:

<u>Option A</u>

  • Unit Rate = $2.49 / 24
  • Unit Rate = $1.04 per bottle

<u>Option B</u>

  • Unit rate = $6.00 / 48
  • Unit rate = $0.13 per bottle

<u>Option C</u>

  • Unit rate = $1.86 / 12
  • Unit rate = $0.16 per bottle

Option C has the lowest rate, hence it is the best deal.

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Find the value of x and the measure of the angle labeled 3x
mafiozo [28]

Answer:

27

Step-by-step explanation:

45+27=72 and the overall angle is 72

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Svetlanka [38]

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A

Step-by-step explanation:

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The midpoint of is M(4,-3) One endpoint is G(-2,2). find the coordinates of end point​
motikmotik
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Choose correct response
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D

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2 years ago
Evaluate Dx / ^ 9-8x - x2^
Solnce55 [7]
It depends on what you mean by the delimiting carats "^"...

Since you use parentheses appropriately in the answer choices, I'm going to go out on a limb here and assume something like "^x^" stands for \sqrt x.

In that case, you want to find the antiderivative,

\displaystyle\int\frac{\mathrm dx}{\sqrt{9-8x-x^2}}

Complete the square in the denominator:

9-8x-x^2=25-(16+8x+x^2)=5^2-(x+4)^2

Now substitute x+4=5\sin y, so that \mathrm dx=5\cos y\,\mathrm dy. Then

\displaystyle\int\frac{\mathrm dx}{\sqrt{9-8x-x^2}}=\int\frac{5\cos y}{\sqrt{5^2-(5\sin y)^2}}\,\mathrm dy

which simplifies to

\displaystyle\int\frac{5\cos &#10;y}{5\sqrt{1-\sin^2y}}\,\mathrm dy=\int\frac{\cos y}{\sqrt{\cos^2y}}\,\mathrm dy

Now, recall that \sqrt{x^2}=|x|. But we want the substitution we made to be reversible, so that

x+4=5\sin y\iff y=\sin^{-1}\left(\dfrac{x+4}5\right)

which implies that -\dfrac\pi2\le y\le\dfrac\pi2. (This is the range of the inverse sine function.)

Under these conditions, we have \cos y\ge0, which lets us reduce \sqrt{\cos^2y}=|\cos y|=\cos y. Finally,

\displaystyle\int\frac{\cos y}{\cos y}\,\mathrm dy=\int\mathrm dy=y+C

and back-substituting to get this in terms of x yields

\displaystyle\int\frac{\mathrm dx}{\sqrt{9-8x-x^2}}=\sin^{-1}\left(\frac{x+4}5\right)+C
4 0
3 years ago
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