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Arlecino [84]
2 years ago
6

Given the function defined in the table below, find the average rate of change, in the simplest form, of the function over the i

nterval 4\le x \le 54≤x≤5.
xx f(x)f(x)
44 55
55 1010
66 2020
77 4040
Please Help
Mathematics
1 answer:
vekshin12 years ago
4 0

Answer:

im stuck on that question too funny bc im in your class and caught u cheating

Step-by-step explanation:

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The correct answer is 5 1/2 because if it weren’t simplified it would be 6/2 which makes the numerator the greatest.
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A table has an area of 12 feet squared and a perimeter of 16 ft. What are the dimensions of the table?
lana [24]
The dimensions are 2 ft. by 6 ft. 2*6 is 12, the area. 2+2+6+6 is 16, the perimeter.
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3 years ago
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Chris's new car gets 42 miles per gallon. What is the equation that represents y, the total miles driven on x gallons of gas? x
Lena [83]

Answer:

y = 42x

Step-by-step explanation:

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3 years ago
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Can someone solve this real quick?
Fudgin [204]

Answer:

n = -4

Step-by-step explanation:

Start off by remembering PEMDAS which first P means parenthesis so use distributive property to multiply the 2n + 4 by the 3 in front of it and do the same to the n + 1 and multiply that by the 5 in front which turns your question into 6n+12-2=1+5n+5 so now i'd combine like terms on both sides which now gives you 6n + 10 = 5n +6 so now to get the n on one side i'm going to sub tact it from both sides doesnt matter which one you do but to make it easier i'd subtract the 5n from the 6n because the whole point is to solve for n and by doing that you'd already be getting it by itself. so now the question should look like n + 10 = 6 so subtract 10 from both sides to isolate the n and you get your answer n = -4

5 0
3 years ago
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Help with one integral problem?
Illusion [34]

Answer: 2\sqrt{1+tant}+C

Step-by-step explanation:

To integrate means to find the antiderivative of the function. For this problem, we can use u-substitution.

\int\limits {\frac{dt}{cos^2t\sqrt{1+tant} } } \

Let's first use our identities to rewrite the function. Since \frac{1}{cosx} =secx, we can use this identity.

\int\limits {\frac{sec^2t}{\sqrt{1+tant} } } \,

u=\sqrt{1+tant}

du=\frac{sec^2t}{2\sqrt{1+tant} } dt

Now that we have u and du, we can plug them back in.

\int\limits {2} \, du

\int\limits{2} \, du=2u

Since we know u, we can plug that in.

2\sqrt{1+tant}

This may seem like the correct answer, but we forgot to add the constant.

2\sqrt{1+tant}+C

8 0
3 years ago
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